As I understand:
1) when there is only relative velocity, say in Up/Down direction alone: With horizontal (with respect to individual elevator) light emission, the other observer will see the light being emitted at an angle to his horizontal - exactly similar to the case of a ball being thrown...
Some clarification required: Is the accelerating elevator is similar to a stationary elevator on Earth. Does this mean that the light curving will occur in the stationary elevator on Earth?
I was going through the discussion which was very interesting to me.
I was also not clear as to why the work-done as calculated is 2J and 4J in the two cases mentioned in the first post.
Now I think, I have understood .
The basic mistake I was doing was that I was considering the force which...
So, does it mean that the gravity can separate the mixture components in layers?
Well, the context is like this:
We are trying to use Butane + Air mixture in place of Natural Gas in a burner and fire the mixture with additional air. That looks ok.
But worried that when we put of the system...
As I understand, a gas mixture, say 50% C4H10 and 50% Air, will not segregate and form layers with the heavier gas at the bottom even in a sealed container. This is due to the constant movement of gas molecules.
Is my understanding correct?
Does this depend on pressure?
Thanks
Ok,
1) In case of forced circular motion about a point (without gravity), the energy is spent with no output
2) With circular motion caused by equivalent gravitational attraction from the that point, the revolving object is not spending any energy. The rocket need not fire and consequently no...
I am bit confused with some force is applied but no energy spent, like holding some weight in your hand and standing still on earth.
In the moon case referred above, if some mechanism id added to change the angle of rocket firing to keep it always perpendicular to the motion, the moon will...
Could the effect of "Dark Matter" be explained if in the formaul for Gravitational attraction:
F = GMm/d^x
Where x is considered 2 is wee bit less (may be 1.98 or some thing)
I was plying with the Ned Writes calculator to see variation with Red-shift. All calculated with 'FLAT' choice.
I got the table in the attachment below.
Now, I am still to absorb that I am getting the light from an object that was 5.27 GLY away 11.5GY back at the same instant(NOW) as from an...