Recent content by naman chauhan

Ok I get that gain become very heigh at heigh frequency. Sorry I misunderstood the concept. But if gain is varying between 3 to very heigh value then what's the meaning of 3db frequency?

At very heigh frequency the inverting terminal is connected to ground through short capacitor and now if we apply vi then there is a potential difference between the input terminals of opamp so it will produce heigh output. But here at the same time we are getting feedback through 6k resistor...

How? Would you please explain.

I think that the gain is o at very heigh frequency and as gain vary from 3 to 0 the cutoff frequency will be where the gain will be 3/1.414

Yes it does. But at heigh frequency the capacitor is short and 100% voltage is fended back to the opamp. That's why output will be zero

At heigh frequency the inverting terminal is connected to ground. And since it is a negative feed back circuit so the output will also be 0.

Hey thanks a lot. I get it where I was wrong. I thought that ro is directly connected to ground but it's connected to Rs. That's why I am taking Rd||ro. Thanks a lot again.

Hi everyone, I was trying to solve this problem. Here at calculate 3 db frequency the gain should me 1/sqrt(2) times of the maximum voltage gain. So I calculated maximum gain which is 1+6/3=3 ( capacitor will be open for maximum gain). At 3db gain will be 3/1.414 3/1.414=(1+6k/(3k||(1/jwc)))...

thanks a lot for telling me the difference in between gm and rd. I had a missconfussion regarding this concept. thanks for sharing this with me. so Vo=Vds+Vs where, Vds = (Io-gmVgs)*(ro||Rd): here Vgs=-Vs Vds=(Io+gmVs)*(ro||Rd) Vs=Rs*(Io) sum of current source and ro current will be...

as far as my understanding says, gm= Id/Vgs and if the slope of characterstic curve is constant the gm can be approximated as rd. Please correct me if i am worng. In the image attached by you the current source should be open because at the time of calculating output impedence we remove...

well rd is the resistanace offered by FET. Its the internal resistance of the device. It is inverse of the trannsconductance offered by FET. rd= 1/gm

Hi everyone, I have attached an image of fet amplifier in common source configuration. I want to have the ac analysis of this circuit. I am able to figure out the input impedance and the voltage gain. But I can't formulate for output impedance. According to me, while calculating output...

Thanks for your help. But can you please help me out with the mathematics. I have tried it but got struck in the integral.

Hey can somebody tell me the Fourier transform of e^-(pi*t^2)?