- #1

naman chauhan

- 14

- 0

I was trying to solve this problem. Here at calculate 3 db frequency the gain should me 1/sqrt(2) times of the maximum voltage gain.

So I calculated maximum gain which is 1+6/3=3 ( capacitor will be open for maximum gain). At 3db gain will be 3/1.414

3/1.414=(1+6k/(3k||(1/jwc))). Then I solved for the frequency. But I am getting the wrong answer. Can somebody please tell me that wether I am making a mathematical mistake or applying wrong concept.