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A carpenter's square has the shape of an L, as in Figure P12.7 (d1 = 16.0 cm, d2 = 4.00 cm, d3 = 4.00 cm, d4 = 11.0 cm). Locate its center of gravity. (Hint: Take (x,y) = (0,0) at the intersection of d1and d4) (I tried to attach the picture but I couldn't get it to work, so just know the width...

1. A student gets his car stuck in a snow drift. Not at a loss, having studied physics, he attaches one end of a stout rope to the vehicle and the other end to the trunk of a nearby tree, allowing for a small amount of slack. The student then exerts a force F on the center of the rope in the...

I know a couple of these I already asked, but I'm really close and missing something. Could someone help?? 1) A ring of mass 2.53 kg, inner radius 6.00 cm, and outer radius 8.00 cm is rolling (without slipping) up an incline plane which makes an angle of = 36.4°. At the moment the ring is...

There are only 2 problems I am absolutely clueless on; if someone could help me get started on those 2 problems and help me figure out where I went wrong on the others, that would be great. 1. A bowling ball has a mass of 5.00 kg, a moment of inertia of 1.60 10-2 kg · m2, and a radius of...

I have a couple problems that I have started but don't quite know where to go with them. If someone could respond ASAP it would be greatly appreciated as one of them will probably appear on a test tomorrow :) Thanks! 1) A potters wheel (a thick stone disk with a radius of .500 m and a mass...

How do you find angular acceleration when all you have is angular and linear velocity and a radius of a circle? I tried to use the kinematics but all of them require time or theta.

How can you use ùf = (ùi) + á*t to find ùi when you don't know what á is? (alright well you know what those symbols should mean)

A rotating wheel requires 2.93 s to complete 37.0 revolutions. Its angular speed at the end of the 2.93 s interval is 97.1 rad/s. What is the constant angular acceleration of the wheel? I know this should be easy. I'm just missing something. I figured 37 rev = 232 rad (=theta). Then I used...

Great, I have everything ironed out except for 5 and 8. For number 5, using the systems of equations with those two equations, I got v2 to equal -.0586 and thus v1 to be 9.95. Using the formula for KE, I got KE to be 246. Converting that to PE, my height was 5.05, which is impossible! What...

Unfortunately I'm still lost on some of these. I tried some different methods and got a few of them, but I can't get all of them. 1) 54.3 degrees doesn't work in ANY Of the quadrants. 2) The conservation of energy? Alright, so E = KE(I)+PE(I)=KE(F)+PE(F). Which box do you use for...

Unfortunately, she is allowed to pick it up and touch it!

This might sound like a stupid question, but in my physics class we have a game called "Will it float?" It's just like on the tonight show. We pick out random things to put in the water and guess if they'll float or not. My teacher decided to let us try to stump her after several weeks of her...

I'm trying to do these problems by only reading about them in the book and, having not discussed them in class at all, I'm a little weary about some questions. So bear with me if some of the questions seem a little bit stupid .. I'm just starting out with this stuff. There are more questions...

How long does it take an automobile traveling in the left lane at 60.0 km/hr to pull along side a car traveling in the right lane at 40.0 km/hr if the cars' front bumpers are initially 100 m apart? I know the velocity of the car in the left is 60 and the velocity of the car on the right is...

Exxcellent. I got part (a) and part (c) from that. So basically the formula is PE = mgx+(1/2)kx^2. I tried to get part (b) by plugging the known PE into the formula again and solving for x, but that didn't work. I got .0838 m. (d) I got to thinking .. and wouldn't the x value for which KE...