Haha! I just got the email saying there was a reply.. I was just about to post saying I give up, but finally, lol.. I have to say thanks to everyone here because, I really couldn't do it without the help.
I'm starting to get it now, hopefully by the time the test comes I will understand it more!
Okay, sorry about the late reply, been busy with study and everything.1(x-4)-2(x+5)=3(4-x)
(x-4)-(2x+10)=12-3x
x-4-2x-10=12-3x
-x-14=12-3x
-x = 26 - 3x
2x = 26
x = 13
Is that the solution to the problem?
Haha, not only do I manage to not get the answer, but I get worse :P
Yeah, it's x-4 and 4-x.
I'm kind of afraid to post what I got because I know it's going to be wrong again lol.
(x - 4) - (2x + 10) = 12 - 3x
-2x + 6 = 12 - 3x
-2x = 6 - 3x
x = 6
If that's not right, maybe I should...
That's okay, I don't mind the feedback, good or bad, it all helps in the end! Heh, spend a few hours doing maths, you wouldn't think you would slip up on something so small..Sometimes it is the small things that get past though I guess.
What annoyed me a bit was that the book chapter on linear...
Radioactivity Justification
1. The problem statements, all variables and given/known data
1a. Justify the appropriate charge and mass number values for an electron, a positron, a neutrino and an antineutrino.
1b. Justify the appropriate charge and mass number values for a gamma ray.
1c...
Hmm, thanks for the explanation guys!
Yeah, it's the things like that, that I really need to be careful of when working these out when it comes exam time.
Oh. Heh, thanks. so it should be:
K = 1.76 * 1.6x10-19
= 2.8x10-19
So,
Vs = K / e
= 2.8x10-19 / 1.6x10-19
= 1.76 V
Cheers for the help,
really appreciate it!
Nathan
Homework Statement
The work function of caesium is 1.35eV. A photoelectric cell has a caesium surface and is illuminated with monochromatic light of wavelength 400nm. What reverse potential difference must be applied to the tube to just stop a current passing through it?
Homework Equations...
Ah, Cool. Thankyou!
I only recently got good at rearranging equations (I have a physics tutor) so I didn't really think of that, makes it a lot easier.
Cheers
Ok, I think I got it :D
W = hf0
W/h = hf0/h
Cancel out the h on the right side
f0 = W/h
where W = 4.31eV = 4.31 * 1.6x10-19 = 6.9x10-19J
f0 = 6.9x10-19 / 6.63x10-34
= 1.04x1015Hz
So,
v = fλ
v/f = fλ / f
Cancel out the f on the right side
λ = v/f
λ = 3.0x108 / 1.04x1015
= 2.88x10-7m
Yay, I...
Homework Statement
The work function of zinc is 4.31eV. What is the maximum wavelength of light that will cause electrons to be emitted from a zinc surface?
Homework Equations
I'm not sure because, we are given the Work Function (W) which is 4.31eV and we need to find the max. wavelength...