According to the question
for my convenience let alpha=A and beta=B
there are two equations
Tbc*cosB - Tab*cosA = 0 ------i
Tab*sinA+Tbc*sinB=15-------ii
From i
Tbc*cosB = Tab*cosA
=> Tbc=Tab*cosA/cosB dividing by cosB both sides
Placing this value in ii
=> Tab*sinA +...
the figure of the bench i mtalking about is shown in the following link
http://www.sut.ac.th/cste/Oldweb/tools/itl/me/fm/bench.jpg
dont know how to attach a picture
Hi guys,
hope all are fine. i m new here and don't know much about the rules.
well according to the question i have, i thought its the right place.
i ll never mind if it is moved.
anyways
today i studied the simple laboratory hydraulic bench...
i got struck in the part where plunger is...
well the force applied by the gravity of planet is a one thing and force applied by a person on that planet is another thing
its solution is simple G= W/m where W is weight of the object on that planet and a=F/m where F is the force applied by the person on the object in a not known direction
well its not the only action and reaction force on the cart
there is another action and reaction force couple
which the donkey is applying
he is applying force downward and backward
and the reaction force is acting forward and upward
so that's why it moves ...
i think
the energy is initial potential energy at 60m and kinetic energy is zero
and as the ball is dropped
it comes down decreesing the potential energy and increasing the kinetic energy and at the utmost bottom, there is maximum kinetic energy
so kinetic energy increases coming downward...
thats simple
according to ur data,
vi=0 vf=10m/s and t=3secs
u can find acceleration simply by using acceleration formula
a=(vf-vi)/t => a= 10/3 => a= 3.33m/(sec^2)
now putting it in F=m*a where m=mass
F=m*a
now u can find force
about distance u can apply
d= (vi*t) + (a*(t^2))/2...
u haven't mentioned the angle
anyhow
if let us suppose angle = @
the height of edge = y
and
the distance required = x
then
it is making a triangle having one side and one angle known
neglecting velocity
tan@ = y/x => x = y/tan@
from that u can find out the B part also
the...