Physics: Mechanics - Distance & Height Calculation

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The discussion focuses on calculating the distance a snowball travels after rolling off a barn roof and determining if it will hit a man standing nearby. To solve Part A, the initial velocity's vertical component must be considered alongside gravitational force to find the time it takes for the snowball to hit the ground. The distance from the barn can then be calculated using the appropriate trigonometric relationships. For Part B, a projectile motion equation should be established to compare the snowball's height at the man's position with his height of 1.9 m. The importance of accounting for the parabolic trajectory of the snowball is emphasized in the calculations.
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Physics - Mechanics??

hey i got a problem

A snowball rolls off a barn roof that slopes downward at an angle of . The edge of the roof is 14.0 m above the ground, and the snowball has a speed of 7.00 m/s as it rolls off the roof. Ignore air resistance.


Part A
How far from the edge of the barn does the snowball strike the ground if it doesn't strike anything else while falling?

Part B
A man 1.9 m tall is standing 4.0 m from the edge of the barn. Will he be hit by the snowball?
I don't know how to get started a help would be great.
 
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Solve this in 2 parts. First you have the falling body problem.

You need to find the component of the initial velocity which contributes to the falling motion. Use that to find the time the snowball takes to reach the ground. Once you know that time you can compute the distance from the barn.
 
u haven't mentioned the angle
anyhow
if let us suppose angle = @
the height of edge = y
and
the distance required = x
then
it is making a triangle having one side and one angle known
neglecting velocity
tan@ = y/x => x = y/tan@
from that u can find out the B part also
the solution is only mine
so if u feel i m wrong please tell me ...
thanks
 
Naumann said:
u haven't mentioned the angle
anyhow
if let us suppose angle = @
the height of edge = y
and
the distance required = x
then
it is making a triangle having one side and one angle known
neglecting velocity
tan@ = y/x => x = y/tan@
from that u can find out the B part also
the solution is only mine
so if u feel i m wrong please tell me ...
thanks
No, this is not correct. You have forgotten to take inti account gravitational force in the motion. The path followed will be parabolic and not a straight line.
Follow Integral's advice.
For part B, you had better make an eqn in x and y for the projectile by eliminating time from the two eqns for x and y.Then put x value of the man in the obtained eqn, and see if the y value is greater than or less than the man's height.
 
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