Great.. So if I use that equation then I am getting-2 (6-r^3)^(1/2) + C
But the book says it should be -4(6-r^3)^(1/2) +C
What am i missing?
(thankyou so much for the help!)
What happens when you are taking the integral of something like this...
∫\frac{6r^2}{\sqrt{6-r^3}}
I tried:
u = 6-r^3
du = 3r^2
but i cannot get the correct answer. Help would be great!
1.The question is Evaluate the Integral \sqrt{1+7s}ds
2. Ok, so I've tried this problem but I'm not coming up with the correct solution. Could you help me.
3. This is how I'm handling the problem.
Evaluate: (1+7s) ^1/2
= \frac{2(1+7s)^(3/2)}{3} +C
The...
Evaluate the integral (help)! sin2x dx b=pi/8 a=0
∫sin2x dx b=pi/8 a=0
I'm having a little trouble finishing out the problem. This is what I've got so far.
u=2x
du=2dx
du= 1/2dx
1/2∫sin(u) du
(-1/2)cos u
(-1/2) cos 2x
[(-1/2)cos2(pi/8)]-[(-1/2)cos(2(0))]
? +...
Hey,
Okay, so If I set x to equal zero, then, f'(x) equals 0.
Basically I'm having problems with this whole set of problems. I'm having a hard time wrapping my head around critical points. So what you're saying is:
To find a critical point:
1. find the derivative of a function...
Critical Points, intervals, local max/min help! Calculus.
1. I need help with a homework problem that I just cannot get right. It asks: Answer the following questions about the functions whos derivative is given below.
f'(x) = (sinx +1)(2cosx +\sqrt{3} ), 0\leqx\leq2∏
a. what are the...