Recent content by nerdeagle24

Yes. But what about sigma xy and sigma yx? I know they are equal but how do you calculate them?

I got to start with part A. I will look at the signs as well for part b. How do I even start part A?

I also think sigma xy = sigma yx

I am really stuck on part a. For part b: strain x = (1/19*10^9)(137000+.36*95000) strain y =(1/19*10^9)(-95000-.36*137000) Is this right? For part c: sigma xx'=(sigma x+sigma y)/2+(sigma x -sigma y)cos(2*28)/2+sigma xy sin(s*28) sigma yy'=(sigma x+sigma y)/2-(sigma x -sigma y)cos(2*28)/2-sigma...

Pressure =F/A

Pressure = F/A

So I got a is elongation. For part b and d, I am unsure where to start. For c, i got compression and for e, I put that the dotted line is the red block

I am really just totally stuck. I think you need to find force being applied onto the rod but I cannot figure that out

I see another mistake. I am sorry. So my equations are: angular acceleration = a/r .5MR^2*angular acceleration=T*R mg-T=ma where a is defined as down T = m(g-(angular acceleration/R)) Plug in second equation and solve for angular acceleration = (.5MR+(m/R))/mg

I realized I made a mistake: So my equations are: angular acceleration = a/r .5MR^2=T*R mg-T=ma where a is defined as down So we get from the third equation: T=m(g-a) and the second equation: T=.5MR Set these equal to each other and solve for a: a = g-(MR/2m) where big M is mass of cylinder...

I ended up with angular acceleration = (mass cylinder*R/2*mass weight+g)/R Is that right?

Oh ya. So angular acceleration=a/R. So we can find angular acceleration and then use angular acceleration * t = angular speed?

So we have two equations but three unknowns (angular acceleration, tension, acceleration of mass)? What else should I look at?

I am saying up is positive a

Ya. I mistyped that. I made an edit hahaha. so we get tension*R=I*angular frequency?