the last line in my previous post i had difficult editing until now it should read:
\frac{\ln(MVE) - \ln(MVB) - \ln(CF)}{ \frac{d_{o}+d_{1}}{D}= \ln(1+ R)
I'm still having trouble editing the latex, but I do recognize that the denominator should have (do + d1)/D.
how do I isolate 'R'??
Thank you for the helpful comments. I concur with the faulty explanation part, none the less I still want to figure it out. I should probably explain a bit more about what I’m trying to figure out. The formula is for computing the time weighted return of a portfolio. This formula is used in...
the way they presented it was that they 'assumed' R=.1259 now I will type line by line:
3000 = 2500(1+.1259)^(31/31) + 175(1 + .1259)^(15/31)
3000 = 2500[ln(1+.1259) x (31/31)] + 175[ln(1 + .1259) x (15/31)]
3000 = 2500[ln(.118554) x (31/31)] + 175[ln(.118554) x (15/31)]
3000 =...
this problem is an excerpt from an explanation of a time wieghted performance method. I feel that if I can follow this part the rest of it will make sense. now i know the answer is .1259 but I'm a little fuzzy on how exactly they got that, and their 'step by step' seems to miss some steps. it...
ok I have this limit question that was done in class but i didn't catch it at the time but they grazed over a step where I'm not sure what the reasoning was.
\lim_{n \rightarrow \infty} \left( 1 + \frac{1}{n + 1} \right)^{n} = \lim_{n \rightarrow \infty} \left( 1 + \frac{ \frac{1}{n} }{ 1 +...
ok good hint i think so far:
\mid(x+1)^{3} - 1\mid < \epsilon multiplied out then extracting the factor x:
\mid x \mid \mid x^{2} + 3x + 1 \mid < \epsilon
\mid x \mid < \frac {\epsilon}{\mid x^{2} + 3x + 1 \mid}
now this is in terms of what delta is greater than. At this point I am...
OK I probably have some dumb questions here but it might be partially due to the lack of examples at my disposal and minimal explanation in my text.
\lim_{x\to{0}}(x+1)^{3} = 1
\mid f(x) - L \mid < \epsilon
\mid(x+1)^{3} - 1\mid < \epsilon
now I know that delta is as follows:
0 <...
thank you , i have found my errors
\lim_{n\rightarrow\infty}(\frac{n+1}{n})^{n+1} = \lim_{n\rightarrow\infty}(\frac{n}{n} + \frac{1}{n})^{n+1} = \lim_{n\rightarrow\infty}(1 + \frac{1}{n})^{n+1}\\
\lim_{n\rightarrow\infty}\left(1+\frac{1}{n}\right)^n \left(1+ \frac{1}{n}\right) = e \times...
no I did not realize that \left(1+\frac{1}{n}\right)^n \left(1+ \frac{1}{n}\right) I guess that would make the limit equal to e^2?
as far as the second problem I don't know what exp(x) is but i recognized that I can get things to look more like e...
find the \lim_{n\rightarrow\infty}(\frac{n+1}{n})^{n+1} =
so far what i have is
\lim_{n\rightarrow\infty}(\frac{n+1}{n})^{n+1} = \lim_{n\rightarrow\infty}(\frac{n}{n} + \frac{1}{n})^{n+1} = \lim_{n\rightarrow\infty}(1 + \frac{1}{n})^{n+1}\\
I know this has got to go to e or something very...
wow... I think I need further instruction on the binominal expansion. I'm a bit confused (not in the algebra afterwards, but how the part with the 3! term:
\frac{1}{3!} \times \frac{(n + 1)n(n - 1)}{(n + 1) ^ 3}
this is probably due to my misunderstanding of this theorem but why is there...
Thanks for the latex info, i was wondering how to enact the various notations.
Before I continue with the proof I want to verify that I'm using the binominal theorem correctly as well as latex...