Understanding the Limit as n Approaches Infinity in Calculus

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ok I have this limit question that was done in class but i didn't catch it at the time but they grazed over a step where I'm not sure what the reasoning was.
\lim_{n \rightarrow \infty} \left( 1 + \frac{1}{n + 1} \right)^{n} = \lim_{n \rightarrow \infty} \left( 1 + \frac{ \frac{1}{n} }{ 1 + \frac{1}{n} } \right)^{n} = e
I see the multiplication of one in the form of 1/n over 1/n and i know that \lim_{n \rightarrow \infty} \left( 1 + \frac{1}{n} \right)^{n} = e and i can see the similarity and possible substituions...but what happens to the 'n' exponet since it doesn't substitute nicely?
 
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I see no reason to divide the numerator and the denominator by n. You can simply use a substitution like m=n+1. Or write:
\lim_{n \rightarrow \infty} \left( 1 + \frac{1}{n + 1} \right)^{n} = \lim_{n \rightarrow \infty} \left( 1 + \frac{1}{n + 1} \right)^{n+1}\cdot \frac{1}{1+\frac{1}{n+1}}
 
I think I'm a little more confused now...I do agree that i don't see what dividing by n did to help.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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