Homework Statement
f(x)=(2x+1)^11 (5x-1)^9Homework Equations
The Attempt at a Solution
f'(x)=[(2x+1)^10 (5x-1)^8] * (200x+23)
Where does the +23 come from, I don't get it. I get the rest.
I don't think it's possible to solve that without having a.
You have:
T-38sin(a)-(0.26)(N)=3.8a
+ 55-T=5.5a
It would be 38sin(a)-(0.26)(N)+55=9.3a
You can't put in the normal force because you need acceleration to solve m1gcos(a) and you can't get rid of that 38sin(a). I'm guessing...
Hey, thanks that was really helpful! I didn't think of dividing by t^7.
That made it easy! Thank you! I'll remember this if I get another similar problem!
Homework Statement
In the figure below, m1 = 3.8 kg, m2 = 5.5 kg, and the coefficient of kinetic friction between the inclined plane and the 3.8-kg block is μk = 0.26. Find the magnitude of the acceleration of the masses and the tension in the cord...
Homework Statement
This is the last of 10 calculus problems I have to do this week (besides the one I have half finished) 7/8 so far :). This problem asks if the function is continuous and differential. I don't know how to graph this though. Can somebody help explain, I only need to know how...
Homework Statement
f(t)=\frac{t^5 + t^6 - 1}{t^7}
Homework Equations
The Attempt at a Solution
This is different than the other problems I've been doing.
My first guess would be that I would do this:
f(t)=\frac{5t^4 + 6t^5}{7t^6}
Is that the final answer or is there another...
Wait, ok so
T_{2}=T_{1}cos(50)
so
T_{1}sin(90)+(T_{1}cos(50))sin(50)-F_{g}=0 right?
T_{1}=0.670F_{g}
T_{1}=590/.670=880.597N
This doesn't seem right, what did I do wrong?
https://www.physicsforums.com/showthread.php?t=259689
In that thread how did the person figure out the contact force between mA and mB? I know they got the acceleration by doing F/mA+mB. But I don't get how they got the contact force, because all the blocks are equal mass. Something like...
0=22.1m/s^2+2a(55.3)
-110.6a=488.41m/s
a=-4.416m/s
0=22.1m/s^2+(-4.416m/s)t
22.1m/s^2/4.416m/s=5.004s
t=5.004s
Is this right?
How do I get mass from this? F=ma right, so m=F/a or 12.6=m(-4.416)
or m=12.6/-4.416. But it doesn't seem to work...