An elevator is running with a 25hp motor. to double the lift speed a ____ hp motor is required.
To double the lift speed should we just times 25 by 2 and get 50hp motor. Or is there something more to this.
If compression of a spring is doubled, the stored energy increased by a factor of?
I think that the stored energy is increased by a factor of 2.
Right?
ok, this is what i figured out so far
mgh=1/2mv^2 which m can cancel out gives gh-1/2v^2 which can give me h which is
h= v^2/2g which I can solve for is 12^2/ 2*9.87m/s = 7.3m
is this right?
A .050-kg ball is shot at a velocity of 12 m/s by an upward-slanting cannon. At its maximun height, the kinetic energy of thew ball is 24J.
a) Tha max. height is?
b) the angel of the cannon to the horizontal is?
I really don't know where to start on this question. If someone can...
Okay I see what you are saying I found the force instead of work?
1/2*2500N/M*(.060)^2= 4.50J
1/2*2500N/m*(.080)^2 -4.50J= 3.5J
Now how do I find the max height, I am confused about that part
A spring having constant of 2500N/m is compressed 6.0cm and then additional 2.cm. Then the compressed spring is used to propel a 0.25-kg ball vertically upward.
a) The additional work done on the spring in compressing te final 2.0cm was ?
b) the maximun heignt of the ball was
part...
The second part has friction and the question is
In the question above, if the coefficent of friction is 0.250
a) The work done on the box was?
b)the final velocity of the box was ?
And I set it up like
part a =
3kg*9.87*sin(20) = 10.05
3kg*9.87*cos(20)= 27.62
Un=...
Okay, I am sorry for the confusion. This is a two part question the first part is frictionless, and it states..
A 3.00kg box, initially at rest, slides 1.50m down a frictionless plane inclined at 20degrees to the horizontal?
a) The work done on the box was ?
B) the final velocity of...
Ok in the first question , you said used the equation
mg*sin(20)-(mu)mg*cos(20). And mu=frictional force. However in the first equation we are to asumed there is no frictional force because it is no stated. So this equation is used for the second question where frictional force is given?