The bar is sitting on top of the plate with 40 lbs applied, the plate slides forward the bar never moves forward or backwards, but can fall through the gap or opening the force of impact on the plate can create. The force of impact doesn't have to move 40 lbs just simply slide under it. And I...
The plate is on a 45 degree angle and wants to slam forward but can not because of the 40 lbs of force keeping it in place. The 1 inch flat bar rests on the plate 1/2 inch deep which both are smooth on the surface. speed of 5 ft x 10 lbs = > amount of work to move the plate forward 1 1/2 inch...
A Iron flat bar 1 inch wide resting on the edge of a 1/4 inch thick plate, there is 40 lbs of force applied by the iron bar on the metal plate 1 inch by 1/2 inch. The plate that is 1/4 inch thick can roll forward by gravity because the plate is resting on ball bearings that allow the plate to...
The 10 lbs ball is rolling down hill and will stop upon impact at the end of the tube. Let's say 1 inch wide bar laying on 1/4 thick part of the half tube with 40 lbs of force holding the end of the tube from rolling downhill by way of gravity on ball bearings. Kamerling you believe the 10 lbs...
Ok, let's say we have a bowling ball or a round weight of 10 pounds and have it roll down hill on a half tube that is 5 ft long with a 45 degree slope and at the end of the tube there is a stopping point or catching point. At the end where the ball stops a small portion of the tube can slide...
Ok let's say we have a ball weight or round weight of 10 pounds and roll it down a tube or half tube that is 5 ft long and at a 45% slope and at the end of the tube there is a stopping point. The end of the tube or the place where the ball stops is attached only by bearings that slide forward...
Question: On one side of a wheel there is 50 lbs of weight, if the wheel is released the weights would rotate with the wheel until the weights where at the bottom and stop. Let's say this wheel has a shaft in the middle of the wheel that turns as the wheel does, if you put weights on one side...
WTx5/WTx1+1/4 = WT3 3/4 A beam that is centered and balanced. You can apply wt to one end and it will move downward and raise the end with no weight. If you apply wt on the other end which is a 1/4 more it will move downward raising the other weight. Once the weight is removed there is a 1 1/4...
the beam is never balanced by weight. It is balanced by length. The stationary is 1/4 % more wt than on the other end that is lifted wt for rotation. The wt that rotates is multiple. Let's say 5 wt at 20 lbs = 100 lbs. These are in rotation, but removed and replace one at a time. The...
I believe perpetual motion is impossible. I believe that weight + motion = torque and torque can be used for work. Weight in motion on one side of a wheel creates motion, gravity will provide torque. I believe physics will make it work (not forever) but for a long long time. Weight (gravity)...
The balanced beam or scale will simply teeter toter by weight. The Leverage bar will rotate with the wheel. The leverage bar will release the balanced beam once the weight has reached the end and the weight at the end will hinge and a pin will pull to allow the bar to continue to rotate and the...
wt in motion =torque. It is possible by removing one weight at a time near the bottom of the wheel during rotation. The way to return the weight back to the top of the wheel is by way of stationary weight on a balance beam. The stationary weight on the other end of a balanced beam or scale will...
The question is how to continue to elevate weight to produce motion that will give the end result torque? Motion will take place if wt is on one side, but lifting the wt on the same wheel balances and no rotation will occur. I believe if you have continued rotated wt on one side of a wheel it...