Recent content by Nigzzzz

  1. N

    Air in the Lungs thermodynamics help

    woops forgot the n that's why
  2. N

    Air in the Lungs thermodynamics help

    OHHH so you use PV = nRT 101300 x 0.005270 = n(8.314)(36.04 + 273.15) n = 0.208 moles OK i think i get it! hahaha
  3. N

    Air in the Lungs thermodynamics help

    but that would only be useful in giving me the number of moles in the lungs after inhalation? and it says that he exhaled to the surface to find the number of moles after exhalation?
  4. N

    Air in the Lungs thermodynamics help

    it says that he slowly inhaled by 4.080L with a residual volume of 1.190L so after inhalation he would have 5.270L, would this be the volume constant in the ascend?
  5. N

    Air in the Lungs thermodynamics help

    would that mean it remains at the inhaled capacity - 4.080L? or the difference between 2 volumes?
  6. N

    Air in the Lungs thermodynamics help

    have to assume that lung pressure is the same as air pressure as no other pressure is given so 3.00atm, and it's provided that lung temperature is at 36.04 °C, since the person exhaled all the way i would assume the remaining volume would be 1.190L
  7. N

    Air in the Lungs thermodynamics help

    A submarine has run into trouble and is stuck at the bottom of the ocean. Several people are on board and must make their way to the surface without any diving gear. The air pressure aboard the submarine is 3.000 atm. The air temperature inside the submarine is 18.02 °C and you can take body...
  8. N

    Newton's Law: sliding down a slope

    A snow sled, with total mass 80.0 kg, is lowered at constant speed down a slope of angle 60.0° with respect to the horizontal, for a distance d = 14.0 m. The coefficient of kinetic friction between the sled and the snow is 0.290. Note: g = 9.80 m s–2. 1. What is the work done by the friction...
Back
Top