Recent content by Nikarasu M

wha? I've missed a lot of basic stuff at university (sort of jumped ahead via some credit I perhaps shouldn't have got) and school was a long time ago so a lot of these rules of thumbs and tricks go way over my head... Although here I am doing a masters in engineering - you might say 'lol'...

Hello all, I'm working through old exams for an electrical subject (no solutions given) and I think I've gone wrong somewhere and been left with something I'd like to learn how to work with anyway: \frac{50}{(s+\frac{1}{s}+1)^2-s^2} \frac{50}{2s+3+\frac{2}{s}+\frac{1}{s^2}}\times...

I ended up with t then u, s and p substitutions ! but I found a much easier way using: (the part in parentheses) Wolfram-Alpha led me down a longer and more arcane path (in terms of the trig identities used) ... bah ! ...guess in the long run I don't mind the exercise :rolleyes:

its been a while tis all... catching my tail everyday

Nice, Thanks for that - exactly what I needed :-p I wonder if there is a resource of examples of most/all of these tricks ? Many textbooks and coursebooks show you a couple of them in (unrelated) examples and then leave you on your own. I'm at a new university now and it seems there...

Hello, Say I'm working with ∫ sqrt(1-cos(t)) dt I end up with a substitution of u = 1-cos(t) and dt = du/sin(t) sub back in: ∫ sqrt(u) / sin(t) du Still got a t in there ... hrrmmm So I go to wolfram alpha for some inspiration and 'show steps'...

My question was mostly re. the simple example you find in math textbooks - maybe I need to read up more on physics. Does this function model a physical process ?

Thanks Chris, I see what you're saying here - I'll ponder it for a while and see how it sits (first read, I'd say it's sitting well) Nick

Just realized my calculus is a bit off in my original post - but it shouldn't affect the logical flow of my query ...

ok, I fear an infinite regression of questioning now ;) so, you're saying if you zoom in on the step function you'll see it's actually curved - differentiate this and eventually you'll end up with what looks like another step function - zoom in again - it's also curved - and so on ...

ok, so then jerk and jounce have the kink then discontinuity ? Or some other nth derivatives ? Or you're saying the kinks and discontinuities end at the infintiy-th derivative ? (what is it called ?)

Hello, Something on my mind today... As you keep differentiating functions that are sometimes used to represent the displacement of objects you eventually end up with a function that has discontinuities and jumps in its path. Simple example for the sake of illustration - an object at...

sorry mods - wrong forum ... please delete

https://www.physicsforums.com/showthread.php?t=400913

oops thread here: https://www.physicsforums.com/showthread.php?t=400913