Recent content by nlsed

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    Capacitor (currents, resistors, etC)

    the bulbs are in a series. the 1st diagram is just wire connecting bulb to batteries and a wire connecting the bulb to the + side of the capacitor. a wire connecting battery to capacitor on - side. 2nd diagram is wires connecting + and - side of the capacitor with 2 bulbs in between them
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    Capacitor (currents, resistors, etC)

    Homework Statement A capacitor is charged through one bulb and then discharged through two bulbs. Mark each of the following statements true or false. a) The same amount of charge flows during charging and discharging. b) More charge flows through the single bulb than through the two...
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    Calculating Work & Displacement of a Piston w/ Fuel Energy

    Homework Statement The Internal energy of fuel in a combustion chamber increases by 75J due to 130J of heating. How much work can be done by the piston? How far does the piston move while pushing with 5000N of force? Homework Equations The Attempt at a Solution Since they gave us...
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    Calculating the Mass of a 500N Barbell Lifted 2.2m from the Floor

    Homework Statement A 500N barbell is lifted 2.2m from the floor b)What is the mass of the barbell Homework Equations The Attempt at a Solution b) I have no clue how to convert N to kg.. I don't think its possible..
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    Kinetic energy (Force and d(x))

    Homework Statement If no energy is dissipated , how much KE does an object gain if a) A 10N force is applied for 5m b) A 20N force is applied for 2m Homework Equations The Attempt at a Solution I know there is work being done if an object moves causing it to have KE. I think work is Force *...
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    Rewriting expression of logarithm

    ooh~ log55 + log5x2 = 1+log5x2 = 1 + 2log5x2! thank you so much
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    Kinetic Energy problem i think

    Thank you very much! :!)
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    Kinetic Energy problem i think

    so is this right? since m is constant it is just 1kg 1/2mv2 1/2(1kg)(10m/s)2 = 50 joules 1/2(1kg)(20m/s)2 = 200 joules 1/2(1kg)(30m/s)2 = 450 joules KE for (10-20m/s) = 150 joules KE for (20-30m/s) = 250 joules So accelerating from 20-30m/s requires 100 more joules of energy?
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    Rewriting expression of logarithm

    Homework Statement Rewrite the expression as a sum, difference or multiple of logs. log55x2 Homework Equations The Attempt at a Solution log55x2 = 2log55x = ...
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    Kinetic Energy problem i think

    Homework Statement What takes more energy? Accelerating a car from 10-20m/s or from 20-30m/s? Why? Homework Equations The Attempt at a Solution Since KE = 1/2mv^2, I suppose the higher the velocity is the more kinetic energy the car will have, but I have no clue how to solve...
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