Recent content by Noirro

OK thanks!

Homework Statement Thin parallel plate capacitor is connected to a U=600 V current source. Find the electric current flowing in the circuit if one of the electrodes is pulled at v=6 m/s velocity. The electrodes are square (l=10 cm), the distance between them is d=1 mm.Homework Equations...

Homework Statement Hey there! I have simple problem: To start a spark in a car ignition system, voltages of 5-17kV are required. A transformer with winding ratio 1:100 is used with a 12V battery, so we get a 1200V voltage. How are higher voltages achieved in such systems? Thanks

I think I wouldn't. There would be so much I could do if I didn't have to sleep since lots of time would be saved.

I understand now. Thank you very much!

I believe the energy is now W=\frac{2\epsilon_{0}S}{d-d_{1}}U^{2} Then maybe the work that is to be done is the difference of energy that the capacitor contains with and without the inserted plate?

Great! The resultant capacitance should be C=\frac{4\epsilon_{0}S}{d-d_{1}}

Then they are connected in series. I think each one of those two capacitors has a capacitance of C=\frac{2\epsilon_{0}S}{d-d_{1}}

I think that capacitance will be greater when the plate is inside rather than when it's outside. Am I right?

Homework Statement A metal plate, which is d1=0.5mm in thickness, is put in parallel between the electrodes of a capacitor. Surface area of capacitor's electrodes is S=100cm2 and distance d between them is 2mm. What is the work that is needed to be done to remove the metal plate when capacitor...