Okay, I worked it out and finally got it. I now see what you were saying, in terms of looking at it as orbital speed. That's what made it link. Thank you! I have an exam today and that was from my example problems sheet :smile:
What power must a man expend on a 100-kg log that he is dragging down a hillside at a speed of 0.50 m/s ? The hillside makes an angle of 20 degrees with the horizontal and the coefficient of friction is 0.9
m = 100kg
v = 0.50 m/s
\theta = 20 degrees
\mu = 0.9
From here I thought that...
Okay, problem reads :
The moon orbits the Earth in an approximately circular path of radius 3.8 X 10^8 m. It takes about 27 days to complete one orbit. What is the mass of the Earth as obtained from these data?
I started with
\frac {mv^2}{r} = G \frac {Mm}{r^2}
I did some...
The sentence starts out as such:
Momentum and energy are only two of the many [SIZE="4"]passive forces in the world. It is important to understand how momentum and energy function in a system to fully grasp their concepts and how the two forces affect and conserve themselves in a system...
Basketball player is 2m tall. He shoots at 40 degrees over a distance of 10m into a basketball net that is 3.05m. Whats the initial velocity.
d=10m
Theta=40 degrees
Vxi = Vi cos(40) Ax=0 xi=0 xf=10
Vyi= Vi sin(40) Ay=-9.80 yf=1.05 (difference between player and net)...
I just wanted a second check on this. This is a mortar fired at a mountain to cause an avalanche. What is xf and yf given:
Vi=300 m/s
theta= 55 degrees
t = 42 secs
so I found
Vxi= 300cos(55) = 172 m/s
Vyi= 300sin(55) = 245 m/s
Xf = Xi +Vxi*t + (1/2) ax*(t^2)
= 0 +172(45) +...