Recent content by nontradstuden

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    At 30, I am a recent college graduate with no skills

    Thanks for all the advice. I tried to give "Thanks" to all your posts, but didn't know there was a limit. Hopefully, I can use your advice to the best of my ability. I think I may put off graduate school for now. I had planned on starting graduate school at my alma mater in January, but I think...
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    At 30, I am a recent college graduate with no skills

    What would you do in my situation? I'm almost 30 with no career or professional experience. I finished my BS degree in Mathematics a year ago, but I don't know what to do with it. I had planned on pursuing a MS right after, but changed my mind and decided to look for entry level positions. I...
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    Thin Film Interference Problem: A hair is placed at the edge .

    Still very confused. I have a question about the distance given, the distance between the second and fourth dark fringes. The solution given in class today was 0.0008 m= ( 2*3-1)* (400* 10^-9 m * .1 m) / 4*d rearrange and solved for d to get the diameter of the hair. I know this...
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    Thin Film Interference Problem: A hair is placed at the edge .

    Ohh, thank you very much for your help, barryj!
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    Thin Film Interference Problem: A hair is placed at the edge .

    how do I find the fringe number? When I look at problems similar to this they are given a total number of fringes, like 171 dark fringes. How do I find this total number of fringes?
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    Thin Film Interference Problem: A hair is placed at the edge .

    Thin Film Interference Problem: A hair is placed at the edge... Homework Statement Thin Film Interference Problem: A hair is placed at the edge between two 10.0 cm glass plates of n= 1.52. Light of 400 nm wavelength shines on the glass and an interference pattern is formed. If the...
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    How to find the turns ratio between the primary and secondary coils.

    gneill, Thanks for helping. I honestly don't know what I was thinking. I knew the potential of the secondary coil had to be the dielectric constant of air multiplied by the distance AB.
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    How to find the turns ratio between the primary and secondary coils.

    Homework Statement Find the turns ratio across the transformer such that a spark is given off at the points AB. The distance from point A to point B is 5.00 mm. AB is the distance across the secondary coil. The frequency and voltage of the primary coil is given. Homework Equations...
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    Having trouble finding the potential between two positive point charges.

    Edit: The potential at the point is equal to the sum of the two potentials of the two point charges. V= kq_1 / r_1 + kq_2 /r_2 V= (9*10^9 Nm^2/C^2)* (2.37 * 10^-6 C)/ .101m + (9*10^9 Nm^2/C^2)*(26.4*10^-6 C) / .34m = 9.10*10^5 V. The correct answer is 2.34 *10^6 V. I...
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    Having trouble finding the potential between two positive point charges.

    Homework Statement How to find the potential between two positive point charges? I don't know where I'm going wrong. ==I am adding V_1 and V_2. converted mC to C, cm to m, correct value of k. V1= kq1 / r1 v2= kq2/ r2. ==I am adding both of these, but I'm not getting...
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    Finding and labeling equilibrium points between multiple point charges.

    Homework Statement How to find equilibrium points between four point charges? How do you determine whether these equilibrium points are stable, unstable, or neutral? I know the sum of the forces should equal zero, but that's it. How do you determine the stability of the equilibrium...
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    Question about labeling forces and solving for acceleration of a system.

    @haruspex, The acceleration of the two masses connected by the string is defined as negative in the y-direction, I guess. I don't know what I'm doing.
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    Question about labeling forces and solving for acceleration of a system.

    Homework Statement I have a question about labeling forces for a problem that consists of combined motion taking rotational motion of the pulley into account. Set up: table with a pulley on the end. Two masses connected by a string. There is one mass on the table, the other hanging mass...
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    How to find the expected value of a continuous variable with pdf fy= y^(-2)?

    @Simon Bridge. No. That's all I'm given. f(y;alpha)= alpha*y^(-2) 0<alpha<= y< infinity. It says to determine E(Y) and then find the method of moments estimator of alpha.The integral of y*fy gives me [alpha* lny] evaluated from zero to infinity, but isn't it infinity?
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    How to find the expected value of a continuous variable with pdf fy= y^(-2)?

    Homework Statement Find the expected value of a continuous variable y with pdf fy= alpha*y^-2, 0<y<infinity. I know it is the integral from zero to infinity of y*fy, but I don't know where to go from there. I'm then supposed to use the expected value to find the method of moments...
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