number of atoms in FCC gold cube with only the radius given!
1)it is given that the radius of a gold atom sphere is 144.2 pm, gold is packed in an FCC manner
Give the ratio Ns/Nv as a function of L (gold cube side) and a parameter
of FCC latice, knowing that Ns is the number of surface...
what i am thinking is:
in a unit cell we have 1/8 x 8 corner atoms = 1 atom and in the center of each phase we have 1/2 x 6 = 3 then the total number of atoms will be 4
atoms per unit = 4
volume of the cube is L^3 and volume of the unit is a^3 so if we want to know how many units are there in...
Hello i need help in this question
it is given that the radius of a gold atom sphere is 144.2 pm, gold is
packed in an FCC manner
Give the ratio Ns/Nv as a function of L (gold cube side) and a parameter
of FCC latice, knowing that Ns is the number of surface atoms and Nv is
the...
I need to know the number at surface atoms in a cube of a FCC lattice of gold atoms knowing that R= 144.2 pm with respect to L( length of the cube) and a ( length of a unit cell )