Recent content by nvrslep303

Homework Statement Find the derivative of y = sqrt(XX) The Attempt at a Solution I tried using the equation d/dx (ax) = ax * ln a Is this even a right start? The square root kind of throws me off. I'm not sure if this is the right equation to use or not. I was told the answer...

ohhhhh! so its actually 2.5047 / .051 = 49.11 ratio. I wish I didn't mess up so early in the problem lol. Thank you for the help!

hmm. should i not rid of the 1.15 in the hrhea calculation? it seems that the ratio is when the velocity is 1 to 1 and not 1 to 1.15

*it won't take my superscript for the hearth equation* 0 = v2 - 19.62 hearth and 0 = 1.15v2 - .528 hrhea I fixed! :-pNow i have .051v2 = hearth and 2.178v2 = hrhea 2.178 / .051 = 42.705 I know I'm close it says i am! haha. but I'm just confused, if the velocity is squared on both...

So it should be like: 0 = v2 - 19.62h and 0 = 1.15v2 - .528h -v2 = -19.62h -1.15v2 = -.528h (v2 / 19.62) = h and use that?

A 3.07-kg object is thrown vertically upward from the surface of Earth, where the acceleration due to gravity is g1 = 9.81m/s2. The intial velocity is v1, and the object reaches a maximum height of y1. What is the maximum height, y2, if the object is thrown at a speed of v2 = 1.15v1 from the...