Exponential/Logarithmic functions

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SUMMARY

The discussion centers on finding the derivative of the function y = sqrt(x^x). A participant initially attempted to use the derivative formula d/dx (a^x) = a^x * ln(a), which is only valid for constant 'a'. The correct approach involves rewriting the function as y = (x^x)^(1/2) and applying the chain rule or exponent rules. The final derivative is confirmed to be x^x / (2*sqrt(x^x).

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Homework Statement



Find the derivative of
y = sqrt(XX)



The Attempt at a Solution



I tried using the equation d/dx (ax) = ax * ln a

Is this even a right start? The square root kind of throws me off. I'm not sure if this is the right equation to use or not. I was told the answer was

Xx / (2*sqrt(Xx)) but I'm not even sure how to get there given the answer. any hints or help? :(
 
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x=e^log(x). So x^x=e^(log(x)*x). Try treating it that way. Your given equation is only valid for 'a' being a constant. You can handle the sqrt by either using the chain rule or just the rules of exponents. sqrt(x^x)=(x^x)^(1/2)=x^(x/2), right?
 
how about starting by writing as
[tex]y = \sqrt{x^x} = (x^x)^{\frac{1}{2}}[/tex]

then simplify and consider taking the log of both sides and implicit differentiation
 

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