Using the equations I can get:
E=\frac{hc}{\lambda}
\lambda=\frac{hc}{E}=\frac{1240~eV~nm}{3.4~eV} \approx 365~nm
The velocity of the light changes in the medium by v=\frac{c}{n} replacing c in the above by the velocity in the medium gives...
Homework Statement
Nobel prize for physics for blue laser diode using Gallium Nitride with band gap of 3.4 eV and a refractive index of 2.429.
Explain how these parameters determine at what wavelength a Gallium Nitride semiconductor will laser at.
Homework Equations
E=\frac{hc}{\lambda}...
I wrote another expression for above the clouds, where z is the distance from the clouds. The E field from the charges are in opposite directions which is why there is a negative in the expression below:
E_{above}=E_{+}+E_{-}=kq(\frac{1}{(2h+z)^2} - \frac{1}{z^2})
which simplifies to...
Homework Statement
An electric dipole with -q at the clouds of height h, and +q beneath the surface with height -h.
Given q=200 C, and h=6000m
Electric discharge occurs with electric field of 3000 V/m near ground level, and 200 V/m above the clouds.
Find the ranges where discharges are...
Homework Statement
A column of dry air, of cross-sectional area 1m2, has a surface pressure of 1atm. Over the course of several hours during the day it gains 2MJ of energy from radiation and surface heating. There are no horizontal exchanges of energy of mass, and it remains in hydrostatic...