Thermodynamics: Enthelpy and energy change of a column of air

[Nyfinscyf]

Homework Statement

A column of dry air, of cross-sectional area 1m², has a surface pressure of 1atm. Over the course of several hours during the day it gains 2MJ of energy from radiation and surface heating. There are no horizontal exchanges of energy of mass, and it remains in hydrostatic equilibrium.

Does the surface pressure change?
What is the change in enthalpy, internal energy, and potential energy?

Area: 1m²
Energy gain: 2 MJ
Pressure: 1 atm

Homework Equations

H = U + pV
ΔH = ΔU + Δ(pV)
H=U+P = \int^{∞}_{0} ρ(c_v + R)T dz = \int^{∞}_{0} ρh dz
{\frac{∂U}{∂T}}=\frac{3}{2} Nk=C_v

Ideal gas - internal energy does not depend on volume.

The Attempt at a Solution

Surface pressure: Does not change as there is no change in mass of the column and so there is the same volume of air above the location.

I understand enthalpy increases because the internal energy increases from the gain in heating and radiation. But I don't understand how the potential energy increases nor do I understand how the math works. These formulas seem very vague to me.

How does the gain of energy increase the temperature mathematically?

 

[member 553083]

And how can I calculate the change in enthalpy, internal energy and potential energy mathematically?