Recent content by Nylex

Oh, I've got the definition of the step function wrong. Thanks! I almost have the right answer now and it just needs a bit of fiddling :smile:.

Ah OK, yes. Is my last statement correct, about rewriting my original integral in terms of the step function? If I take the (inverse) Fourier transform of the step function u(\omega) and I end up with two terms (i.e. the delta function and the \frac{1}{t} term that I need, how do I get rid of...

Ah yes, of course it is (since the derivative of a constant is 0). Linearity then means I have -i\omega\mathcal{F}[u(t)] -i\omega\mathcal{F}[c] = 1 \Rightarrow -i\omega\mathcal{F}[u(t)] = 1 + i\omega\mathcal{F}[c] So, \mathcal{F}[u(t)] = -\frac{1}{i\omega} -\mathcal{F}[c] \Rightarrow...

Thanks for the limit approach. I'm not too sure where the definition of the delta function there comes from (i.e. I've not seen that before). I think I'm making some small amount of progress looking at the way Ray suggested to do it. For the delta function, you have...

This certainly isn't helping me. I've applied for quite a few postdoc positions now, most of which have been outside my own field. A lot of the time, I don't even get an interview and the places suggest they've had more qualified applicants. I've applied for jobs outside academia, too, where...

I'll have a look at this again post-viva, as I'm pretty busy with revision and panic. Thanks though! Also, no, I've never done any complex variable theory; there was no course on it during my undergrad and I've not needed it during my PhD.

There are other good universities in the UK, besides Oxbridge! Most (if not) all undergrads doing a 4 year undergrad master's do a substantial project in their final year, which is intended to introduce them to research. If you do a postgrad master's, you'll get that experience too. You should...

I'm not a Fortran programmer, but some googling lead me to this. NB: I've not read the code, or tested it.

It also wouldn't hurt to use [code] tags to preserve the indentation, to help readability.

You mean subtracting, surely.

Put all the terms including r on the left hand side and then factor out the r. It might help you to multiply out the brackets on the right hand side first: \begin{equation} r = e\left(k + r\cos \theta\right) = ek + er\cos \theta \end{equation}

It seems absolute crap for people here in the UK, too.

I found one quant job where they preferred candidates to play a musical instrument :/. Is that what companies are having to resort to now, because they get so many applicants?

I'm not exactly sure what you mean by "115152[SIZE="1"]16". You know that each digit represents a multiple of a power of the base, yes? For example, in decimal (base 10), \begin{equation} 123 = 1 \times 10^2 + 2 \times 10^1 + 3 \times 10^0 \end{equation} You're going to need to show...