Recent content by obnoxiousris

Homework Statement A particle in a 3D cubical potential well. The walls are Lx, Ly, Lz long. Inside the well, V(x,y,z)=0 when 0<x<Lx, 0<y<Ly, 0<z<Lz. V= ∞ elsewhere. Solve the TISE to find the eigenfunctions and eigenvalues of this potential. And to normalise the wavefunctions. (Hint: look...

Homework Statement class Person(object): """Defines a person with dob (date-of-birth, string), gender (two-value string), name (string) and age (integer).""" def __init__(self, dob, gender, name): assert (isinstance(dob,str) and dob.isdigit() and len(dob) == 8), 'dob is...

yes, different experiments do give out different results, but since the two clocks are moving with the same speed, won't their rate of time be the same? i meant to say that the speed of the man is 15km/h wrt shore, and will also be 15km/h to an observer standing on the shore, they will not...

GrayGhost: sorry i have read your comment many times and it still doesn't really make sense, are you saying that the even tho the two photons hit the reflectors at different times, the clock on the first hit photon will somehow lag a bit so when the second photon hit the other reflectot the...

I get the train example where the moving and stationary observers don't agree on things being simultaneous (because the speed of light is constant and the events are separated in space), but what about the two clocks? If they are both in the perpendicular direction to motion,having the same...

The example our lecturer uses to illustrate the relativity of simultaneity is a light clock, where a photon is bounced between a reflector and a detector. a tick in the clock means the light has made a round trip in the clock. There are two clocks, one is orientated perpendicular to the...

thanks guys, really helped!

sorry to bring this up again, i have just started special relativity and the constancy of c is a bit confusing, i get how c is the same in all inertial frames but what about accelerating frames? do observers in acceleration still see c as a constant? i have seen many forum posts and they always...

im confused, so how would you find the energy needed to lift the satellite? is it the change in Ek+change in U then?

so the term -G(m1m2)/r in the equation Esum=1/2*mv^2+-G(m1m2)/r is the CHANGE OF U? yes it is indeed positive, change in U= 3.7x10^9 so now its Ek plus the CHANGE IN U?

um, i think it means the energy required to move the satellite from the surface of the Earth to the 400km orbit. at 400km, the velocity of the satellite is 7689m/s so its Ek is 2.96x10^9 J U is -5.9x10^9 J if i use Esum=1/2*mv^2+-G(m1m2)/r then the overall energy will be negative...

yes, i believe so

Homework Statement a satellite of mass 100kg travels in a circular orbit around the earth, how much energy is required to move it to an altitude of 400km? Homework Equations Ek=1/2*mv2 U= -G(m1m2)/r The Attempt at a Solution i took the satellite as the system, so as it moves to...

yes! me and few friends used energy and worked it out! (after much debate) our eqn: spring energy+ gravitational potential energy- work done by friction= kinetic energy of the system after so this means the velocity is the same for both masses? thank you for your patience! i learned alot!

http://www.turboimagehost.com/p/7639040/untitled.JPG.html oh sorry i ddnt realize that. here is the photo