Recent content by Ocirne94

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    Dielectric effects confined inside the dielectric material?

    Thank you. So for other setups without this approximation the polarization density does indeed affect the electric field outside the dielectric's volume, which likely means some double integral to calculate these effects...
  2. O

    Dielectric effects confined inside the dielectric material?

    Consider this setup: I was told that here the fields are E_1=\frac{\sigma}{\epsilon_0}=E_3 (outside the dielectric), E_2=\frac{\sigma}{\epsilon_0 \epsilon_r} inside it. The fields outside the dielectric are the same as if there were no dielectric: they ignore any possible contribution from...
  3. O

    Dielectric effects confined inside the dielectric material?

    Hi all, I am wondering how is it possible that the polarization effects of a dielectric material remain confined inside the material itself. That is: for a LIH dielectric, the equations state that the electric field inside the material is reduced by \epsilon_r. But outside the material, no...
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    Differential form of Gauss' theorem with dielectrics

    Hi, I was taught that (as a rough model with some approximations) within a LIH dielectric the dipoles get a uniform orientation: this implies that no net bound charge can be found inside the dielectric's volume, and only surface charge is present. I definitely agree that the maths allows...
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    Differential form of Gauss' theorem with dielectrics

    Hi, thank you for your answers. There are two ways for those two equations to be compatible inside the dielectric: the first is that \epsilon = \epsilon_0 which I would interpret as saying that the dielectric isn't there. The other one is that the divergence is zero in both cases, which...
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    Differential form of Gauss' theorem with dielectrics

    Hi all, I'm stuck on this incompatibility within the differential form of Gauss' thearem (or Maxwell's first equation) with dielectrics. \vec{\nabla}\cdot\vec{E}=\frac{\rho_{free}+\rho_{bound}}{\epsilon_{0}} \rho_{bound}=-\vec{\nabla}\cdot\vec{P} But with a linear, homogeneous...
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    Constrained mass point subject to elastic force and weight

    I get it from geometry: the spring's square length is r^2(1-cos\theta)^{2} + (sin\theta^{2}) which becomes r^2 + r^2cos\theta^2-2r^2cos\theta+r^2sin\theta^2 the 2 gets simplified with the 1/2 of the elastic potential formula. This (I forgot to say) setting potential=0 at the south...
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    Constrained mass point subject to elastic force and weight

    Hi all, is my solution correct? I was rejected because of this... Homework Statement Consider a mass point (mass = m) constrained to move on the surface of a sphere (radius = r). The point is subject to its own weight's force and to the elastic force of a spring (elastic constant = k, rest...
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