Recent content by Ognerok

Ah, nevermind. Considering 32 is an exact number anyway (a "counting" number) in which sig figs aren't counted in the 32. I guess if it was 3.6 + 32.0000, then sig figs would be counted for the 32.0000 (which is, 4 decimal places vs. 1 decimal place; result should have 1 decimal place).

Homework Statement I need to calculate F = (5/9) (6.5) + 32 using the correct number of sig figs. Homework Equations F = (5/9) (c) + 32 The Attempt at a Solution Got down to 3.6 + 32; should it just be 35.6 or 36?

That makes more sense. But...I thought Q itself was just a constant, you know, an electron's charge...it must be Q in the sense that Q = u/V? :)

Homework Statement While going through a basic electrical engineering overview, I came across the equation U = QV, which is defined to be electrical energy. For Power, which is explained in the next section, P is basically the derivative of U = QV. I tried following the derivation myself...

Homework Statement Aggregate # of nickels and dimes = 20 coins. If the ratio between nickels and dimes is 2:3, what is cent value of 20-coin set? Homework Equations 2x = 3y The Attempt at a Solution 20 = nickels(x)+dimes(y); ratio = 2x:3y; 2x = 3y; y = 2x/3 20 = x + 2x/3; x...