Recent content by omkar13

ds/s = 2dv/v + 2(cos2t/sin2t)dt If you consider here sin2t=x,then (cos2t dt/sin2t)=dx/x Hence ds/s=2dv/v+2dx/x substituting dv/v=10 and dx/x=10 ds/s=40%. Hence relative error of s is 40%

I think you might be knowing the wavelength of current leds.Just search for other type.I think we can find because the basic difference between two types is that surface emitting led emits in a circular fashion and edge one in elliptical pattern.I din't understand what is meant by odd manner.

Dude what is this P(t)? Is it any other equation or we have to make it as a subject like P(t)= something and plot it?

My dear friend,there are 2 types of leds.Edge emitting and surface emitting.Of them edge emitting leds are better.Just check the properties of it.

dx/dt = 2000-500x/100 =>dx/dt=20-5x =>dx/20-5x=dt=>(dx/4-x)=5dt Integrating it,-ln(4-x)=5t+k(integrating constant) =>x=4-a*exp(-5t) (ln(x) is one of the basic functions in maths)

I tried it and I found that there should be another condition w.r.t. to k too.

We can't say like that because some follow a series and some follow logic.I'll give examples of both.Series'll follow a specified formula. Eg. of logic series:1,2,2,4,3,8,4,16,5,6etc. In this odd positioned nos are 1,2,3etc and even positioned nos are 2,4,8,16 etc.

FOR PART 4: You just expand RHS of give eq. in and equate coefficients of x^2 on both sides and you'll get it.

My method is that I draw a rough sketch of function.If f(t)→ 0 while t→∞,then we can say that integral is convergent as integral is area under the curve.

The condition y(1)=0 is given in order to find constant.THE PURPOSE OF GIVING BOUNDARY CONDITIONS IS TO OBTAIN CONSTANTS AFTER INTEGRATION.

Negative resistance is just a property shown by some elements like UJT(in normal ac circuits),GUNN DIODE(in microwave circuits) etc.All of them exhibit that property in a range of ac voltage.Hence as far as I know,there is no such dc circuit.

Sorry for late reply.I understood that you are confused because you are thinking that we Plot magnitude Vs frequency.It's not the case.We are plotting Re(G(jw)H(jw)) on X axis and Im(G(jw)H(jw)) on Y axis as Frequency increases(we are not showing frequency).We are interested in stability etc. of...

Please refer to the content of followig link. lpsa.swarthmore.edu/Root_Locus/RLocusExamples.html I think you will be able to understand.

I think definitely we can do it because the capacitors are at output section and definitely it will get some output either voltage or current.Isn't it?

As far as I know a capacitor needs a resistor to discharge.So I think in above circuit considering ideal situation,they can't discharge.If I m wrong please tell me.