Recent content by OONeo01

Ok. So √3 which matches with one of the given options doesn't really make much sense. Thanks a lot for the help guys. What was more important to me was how to find the RMS error(of any measurement, not just the volume of a cylinder) rather than just matching answers with options. I guess I...

Could you please explain that, or give some link where it has been explained ? I didn't quiet understand what you meant by that.. X-)

Homework Statement The length and radius of a perfect cylinder are measured with an RMS error of 1%. The RMS error of the inferred volume of the cylinder is.. ?Homework Equations V=∏r2h Hence dV/V=2dr/r+dh/h The Attempt at a Solution I took dr/r and dh/h as 1%. So got the final answer as...

Thanks a lot guys ! Got the Answer :-) Option D, right ?

Homework Statement This is a question asked in one of my papers. A time dependent magnetic field \vec{B}(t) is produced in a circular region of space, infinitely long and of radius R. The magnetic field is given as \vec{B}=B0t\hat{z} for 0≤r<R and is zero fr r>R, where B0 is a positive...

Ok. Thats kind of how I had started and gotten Rf=2R0 even before I had asked this question here. But my concepts were all messed up and so were my equations. Thanks a lot for your patience :-)

Now, at the risk of sounding stupid, can you explain to me how you got Equation 2 ? That was my culprit. I wrote equation 2(for R0 and v1) the same as its written in equation 3(for Rf and v2). I don't want to make the same mistakes the next time I form such equations(I prefer making new ones...

Ok, let me start over again. So far I have, 1.) R0/Rf=v2/v1 2.) P.E.=-GMm/Rf 3.) K.E=(1/2)mv22=GMm/2Rf 4.) Total Energy=-GMm/2Rf 5.) Angular Momentum(in general)=MvRSinθ (θ=90°for a circle) 6.) v12=Gm/R0 7.) Centripetal force=Mv22/Rf 8.) Gravitational Force(in general)=GMm/R2 So...

My solution seems to have gone into a circular orbit as well. I started by calculating the angular momentum of a circular orbit, and now I am back to finding the angular momentum of a circular orbit ! X-) Anyway, how do I write v1 and v2 in terms of Ro and Rf ? I can so far only write v1 in...

K.E=-(1/2)P.E K.E.= (1/2)Mv12 P.E.=GMm/Ro So (since total energy is ≈0), (1/2)Mv12=GMm/2Ro Even if I do the same with v2 and Rf, at best I reach Rf=Ro. But I am unable to understand how to set up equations differently for an Elliptical or bit, and specifically for a circular orbit...

Ok, so I make θ=90° and get Ro/Rf=v2/v1. Now if I can get v1 or v2 in terms of each other, then I can get my answer. So I look for another relationship, I try the force equation, and end up with, mv12/Ro=GMm/Ro2 which even when simplified doesn't take me much further. Then I tried...

Umm.. Point mass AND a Main star ? X-).. I'm not convinced by your method, can you set up some equations for what you have explained ?

If the total distance is taken to be R, then at a distance R/2. Or alternately if I take the total distance as 2R, then at a distance of R; whichever makes my equations simpler.

Ok, So, the general formula for angular momentum would by mvrsinθ;(sin=1 for circular orbits) Applying it here I get, mv1Ro*Sinθ=mv2Rf Implying, Ro/Rf=v2/v1sinθ Is that right ? I'll give a heads up, I am a bit of a douche, so you'll have to be a bit patient with me. But I will certainly...

Well, the center of the line joining the two stars.