Recent content by Paradox101

Thanks

In a lot of books I have seen the mass number of an element being written on left superscript of its chemical symbol,while my professor and other teachers write it in right superscript.However, it is written at the bottom of the symbol in the periodic table.Which is/are correct, or are all...

Could you suggest any other laser,not necessarily in the visible spectrum but definitely in my low budget?

For a certain science fair working model, what should I use to detect the collimated light of a HeNe laser(in the red;653nm if that is necessary)?After some surfing on the net, I found that I should use a 'photodiode'. The desired result should be solely to detect whether the laser's light is...

But what should I do next?How do I relate these KEs with the height of the incline?

Ok final speed in first case will be twice of average speed( because initial speed is zero)=25/3m/s.so,KE1=mv2/2=625m/18. And final speed in second case will be 2×30×5/18=50/3m/s. Now what?the 2 KEs are different.I'm not sure, but it won't be W=KE2-KE1, right?because that's a different thing.

Are you implying that 4000F= mv2/2? If so, which speed is v?

Kinetic?

CORRECTION: the average speeds are------- 4000/960=4.1666...m/s and 4000/480=8.3333...m/s.

don't know...moved the object against the component of the gravitational force?

so,i have been trying something, is it possible that i could first find t1=960s,t2=480s, then the average speeds are 0.24m/s and 0.12m/s, and 4000F=mgh?

DEvens, I don't think he knows about calculus.If however he did,all he would have to use would be d/dx(s/t)=v [or v=f'(s/t)] and ∫vtdt=s

Hi faiziqb12! Welcome to PF! I can't and won't give the answer directly, all I can do is guide you. First, try recalling the equation of average velocity.Can any variable there be substituted from the first eqn? <Mod note: Removed excessive text formatting>

LOL, sorry, didn't realize that(Australia-----diff. time zone*duh*) Is it wrong though? I mean, s=v/t, where v=15km/hr=15*5/18 m/s, and s = 4000m, so t= s/v=960s(used the calc.). and, a=v/t=(15*5/18)/960=0.00434m/s^2.

Neglect friction.sorry for not adding that.And,just for convenience, I converted the distance and time units(km and hr) to m and s.Now,average speed to the top is given. So, time=4000m/[(15*5/18)m/s]=960 seconds. ⇒a1=v/t=(15*5/18)/960=0.00434m/s2 What next? do i find the mass(if so,how and why?)?