Recent content by PatPwnt

Say I stick half of my body through the event horizon of a super massive black hole. I say a super massive black hole because in this case the event horizon radius will be very large and the tidal forces will not be as strong. Why can't I pull myself out if the force on the part of my body past...

The patent in the link explains that it reduces the work load on the compressor in a car air conditioner by using heat from the exhaust to super-heat the gas directly after it exits the compressor. Other than that it seems to be a normal air conditioner. I am having trouble understanding how...

But, that is not what is happening. If we consider there to be a pulley. It must be considered part of the system. Then the rope pulling down on the side also pulls down on the pulley and it also has a normal force.

I mean that the part of the rope on top of the table stays on the table until it moves over the edge. If the rope isn't moving upward off the table or downward through the table, then the forces must be canceling. That's the rule. So why would the normal force only be the weight of the rope on...

The downwards force beyond the edge of the table still tugs on the part of the rope on the table though. So the normal force must also cancel this out and may be different than just the weight of the rope on the table.

If I have an extended (uncoiled) rope sitting on a table, and part of it is hanging off the edge of the table so that it starts to slide (there is friction), how would the normal force of the table acting on the rope change as it slides off? This has been bugging me for weeks, because people...

Anyone? Just a tiny little hint? Please?

Here is what I think. I know that the center of mass of the rope starts to accelerate. The acceleration has a downward component, call it a_y. Then I know that there is an imbalance between the normal force and the force due to gravity. Let m be the mass of the rope that is hanging over the edge...

0 Joules/sec are necessary, if you are traveling in a vacuum(space) see Newtons first law. Also, the energy required to get up the speed is a little more than you calculated because when you increase your speed, your mass increases as well, see special relativity / einstein. But, your method of...

Thank you. Now, someone please answer to me the following question. If the rope starts to slide off (not at rest anymore), that is, the center of mass begins to accelerate, how does the normal force change during the movement or does it change at all (while the rope remains in contact with the...

A rope of length L sits at rest on a horizontal table with length L/3 hanging over the edge. The rope is mass M. What is the normal force acting on the rope? (I keep having people tell me that it is the product of the mass of only the rope that is on the table with the acceleration due to...

What is the definition of a crash? Two cars that are the same mass and going equal opposite velocities that collide head on will be similar to one of the cars colliding with an immovable wall. Or one of the cars colliding at twice the velocity with the another car at rest.

Yes, the GPE is always negative with respect to the GPE at r=infinity and no, the the GPE is increasing when you go farther out into space. When you take off in a rocket you have to do work the whole time you are overcoming the gravitational force, even as the gravity is getting weaker. The...

Instead, think of an electrically neutral wire with a current going through it. If you are a charged particle, say an electron, at rest with respect to the wire, you do not feel any force from the wire and it doesn't feel anything from you. There is a current in the wire, which means there's...

Thanks for the reply. I figured this problem was easier than it looked at first.