Recent content by Paul L

And therefore should the material constant k be included in the equation when the depression (and hence the elongation) is given. The equation F=(mgl)/(4h) must be wrong since it doesn't include the material constant.

For a perfectly inelastic body k -> infinity. Hooke's law gives x = F/k and F/k -> 0 when k -> infinity. For a perfectly inelastic body, x = 0 for any given force F. If the rope is replaced with a steel rod this would be a completely different problem as a rod can absorb torque and a rope...

I'm not sure if I'm following you, but I tried what you suggested (attachment once again) and ended up with this: F=(mgl)/(4h) I have a bit problems believing that's correct as it would mean that an inelastic rope (k -> infinity) will stretch and bend down equally much as a elastic rope...

The F in figure 2 should be called S. If we call the new length of the rope (the hypotenuse) L, I get the following similarity: L/h = S/F Then, with some algebra (see attachment), I get an equation I'm not sure what to do with.

Tiny-tim is right. The distributed load because of the wind depends on the exposed area. I forgot to take that into account when I explained my way of doing it. However, if the tower has the same exposed area all over it's easy to add this. Say that the area has a width, b and (of course) a...

<< solution deleted by berkeman >> If you need more help, take a look at the attached picture, but try for yourself first! ;) << attachment deleted by berkeman >>

If I've understood your question right this should be something like part 1 in the figure I've attached. That case can be transformed to a free body diagram, see part 2. To find the unknowns we can apply three equations of equilibrium: Sum of vertical forces: This easily concludes that Ay = 0...

The problem: See attachment for figure. (1) A rope with a spring constant k is stretched by a force F.The length of the rope is l (including the deformation). (2) A force mg is then applied at l/2 on the rope. This results in a height difference between the highest (and unchanged point) and...