Recent content by PaulHP

T = 63025*hp/rpm is to find torque in in-lbs, and T-5252*hp/rpm is to find it in ft-lbs..

0.05 hp X 5252= 262.6/300 rpm = 0.88 ft-lb 0.88/3.5 ft= 0.25 lbs of thrust

ah. So, 0.88 ft-lb would be required to counter balance to main rotor and the thrust required for the tail rotor at 3.5 feet would be 0.25 lbs, right?

Thanks, I thought it would, but how would you determine exactly how much thrust would be needed for the tail rotor at various tail boom lengths?

lets say that this is for a model helicopter with .05 hp (37 watts), has blades that rotate at 300 rpm and has a 3.5 foot long tail boom. Wouldn't the required thrust of the tail rotor be cut in half if the tail boom length is doubled?

How can you calculate the amount of thrust needed by the tail rotor of a helicopter to counter the torque of the main rotor?