Recent content by pcandrepair

Law of sines: c/sin(A) = c/sin(B) = c/sin(C) Do I have to solve this as a system of equations to solve for the sides? But where does the given perimeter come into play?

Homework Statement All three sides of an isoceles triangle are given along with its perimeter. Find the length of each side. A=97.433 B=41.283 C=41.283 Perimeter=24.78in Homework Equations p = a+b+c a2=b2+c2 - 2*b*c*cos(A) The Attempt at a Solution Would you somehow find the...

I got it. Thank you!

Homework Statement The Ko meson is a subatomic particle of rest mass MK = 498 MeV/c2 that decays into two charged pions, Ko \rightarrow \pipositive+ \pinegative. Both pions have the same mass, m\pi = 140 Mev/c2. A Ko at rest decays into two pions. Use conservation of energy and momentum to...

Homework Statement An electron in a cathode ray tube is accelerated through a potential difference of ΔV = 11 kV, then passes through the d = 4 cm wide region of uniform magnetic field. What field strength (in mT) will deflect the electron by 10(degrees)? (Hint: is it a reasonable...

Before I submit my answer, would you agree with using conservation of energy and the answer that I got?

So, now at 90% of 172,800 J = 155,520 J Using conservation of energy: 155,520 J = mgh 155,520 J = (8.1 kg)*(9.8 m/s^2)*(h) h = 1959.18 m ? This seems like a large value but reasonable because the mass is not that great.

Homework Statement A fully energized 12V battery is rated as "4 Ampere-hours." Suppose this battery is connected to a motor that is 90% efficient at converting electrical to mechanical power. How high could this battery-supplied motor lift a 8.1 kg mass? Homework Equations V = I*R P =...

Kinetic + potential = Emech (1/2m(Vi^2)) - q(E)*(Xi) = (1/2m(Vf^2)) - q(E)*(Xf) Then we changed the equation to this: qE(20cm) = 1/2(mass of electron)*((Vf^2) + (Vi^2)) Then we solved for Vf: Vf = 3.61697 x10^7 m/s

So the force would be F = (50000 V)*(1.602 x10^-19 C) F = 8.01 x10^-15 N

Homework Statement An electron with an initial velocity of 4.7 x 10^7 m/s in the x-direction moves along a trajectory that takes it directly between the center of two 20 cm x 20 cm plates separated by 1 cm. The plates are connected to a high voltage power supply so that the potential...

Thanks for your help, foxjwill!

When I integrate the field of the semicircle, I come up with a field of magnitude -147,858 N/C...?

we haven't even started studying gauss law yet...

[SOLVED] E-field at the center of a semicircle Homework Statement Calculate E at center of semicircle: A uniformly charged insulating rod of length L = 12 cm is bent into the shape of a semicircle as shown. The rod has a total charge of Q = -6 nC. Find the magnitude of the electric...