Recent content by pcdagr8

most welcome well...your logic seems correct but some problem in units. u say spring constant is 1?? if its 1 it must be 1 cm/kg wt but in si it will be not be so but later you say the force on each spring is 2.5 N it can't be its 2.5kg wt otherwise your soln is correct n btw...

well...i can't help u with this.i don't have any software to make a diagram for you...may be someone else can help...

N is normal reaction ,component of gravity perpendicular to the surface when you are taking the component of gravity parallel to the surface as mgsin20 how are you missing out that perpendicular component will be mg cos20 just draw a free body diagram and resolve the forces...

N is mgcos 20:smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile: :smile:

must be correct btw...its 18.06^2 i think u hav used it in calculations but missed it here

well... you have got that toooooo wrong:smile: :smile: :smile: :smile: :smile: :smile: the boat and chils are a system having same velocity while the package will have some other velocity so... initial momentum=0=finalmomentum = 6.4 X 10 + (boat + chiild) X V -6.4X10=(boat+child)XV...

You are correct ! though it should have been mentioned that the springs are identical but as nothing is mentioned we can take them to be identical

If that's the way you attempted the question you are not going to get anywhere for sure!:smile: :smile:

ohh... why they never teach all this at high school? but this time that doesn't add any problem to my answer as it will eventually be zero neways...Thanks to you ! for correcting me

first of all u haven't understood really what phase difference is... it has nothing to od with angle between the rays... study some more about phase difference articls on net or yourhandy textbook so 60 is not initial phase diff as initial is not given we can take it as zero is uppose next...

HI draw a free body diagram first as plane is moving with const. velocity thrust (in direction of plane)= air resistance + component of gravity in d direction opposite the movement of plane thrust= 1330 + M X g X cos(90-6.09) = 1330 + 1220 X 9.81 X sin(6.09) =1330+1270...

Thanks Al !:smile: but u haven't answered my second question... please see if u can tell me something about it.

well..i am weak in fluid mechanics but i guess the water applies a "FORCE" of friction on the object moving on its surface how can u pull out with constant velocity...without applying a constant acceleration against the force of friction?

going by your logic You mean in pure rolling motion the friction should act backward??

if a rear wheel driven car is accelerated i think... 1. on rear wheels friction is forward 2 on front wheels it is backward my questions- 1.wats d direction of rolling friction on the car as a whole?(is dis question correct?) 2.which wheel will have greater magnitude of friction??