Recent content by peaceandlove

Homework Statement If you are walking towards a mirror at 7 m/s, how fast are you and your image approaching each other? Answer in m/s. Homework Equations --- The Attempt at a Solution I'm not sure how to solve this mathmatically but when I first looked at this question, I just...

Homework Statement http://s619.photobucket.com/albums/tt272/babyazureyoshi/?action=view&current=014.jpg Homework Equations 1) B_x = (µ_0 * I) / 2R at x = 0 The Attempt at a Solution I know that segments BC and DA do not contribute to the magnetic field at O so all I need to know is...

Oh... so if the capacitor is discharging I would use the equation: V = (V_0)*(e^(-t/RC)). So then V = 6.58435. Plugging that into equation 1, I would then get 1.9753*10^-5 C (=19.753 microC).

Homework Statement A 3 µF capacitor is charged to 76 V and is then connected across a 698 Ω resistor. (a) What is the initial charge on the capacitor? Answer in units of µC. (b) What is the initial current just after the capacitor is connected to the resistor? Answer in units of A. (c) What is...

I tried that and I get the same exact answer that I got. I even tried putting it in as 0.57 but that was marked wrong as well...

Homework Statement A steam iron draws 5.3 A from a 114 V line. (a) How much internal energy is produced in 76 minutes? Answer in J. (b) How much does it cost at $0.75/kW*hr to run the steam iron for 76 minutes? Answer in units of cents. Homework Equations 1) U = VIt The Attempt at a...

Could you please explain how you would solve for (b)? Since there are 2 µC at 72 degree intervals along the equation, I tried dividing 2 µC by C, but that is wrong as well.

Homework Statement A sphere with radius 65 cm has its center at the origin. Equal charges of 2 µC are placed at 72 degree intervals along the equator of the sphere. The Coulomb constant is 8.99×10 N·m^2 / C^2. (a) What is the electric potential at the origin? Answer in units of kV. (b) What is...

Oh wow... yet another stupid mistake. Thanks so much everyone!

That apparently isn't the answer... what did I do wrong?

I meant 10^4 since it's in kN/C, so the answer would be -7.8*10^3 kN?

I would think that the x^3 would mean that E is not uniform/constant... -5*10^6 times the integral of x^3 from 5 m to 1 m... which is the same as -5*10^6*[(1/4)x^4] from 5 m to 1 m... which is equal to -7.8*10^5. Is that it?

Homework Statement An electric field is given by E_x = (5 kN/C) x^3. Find the potential difference between the points on the x-axis at x= 1 m and x = 5 m. Answer in units of kV.Homework Equations V = -EdThe Attempt at a Solution V1 = -5*10^6 N/C * 1 = -5*10^6 volts V2 = -5*10^6 * 5 = -25*10^6...

Oh wow! Stupid mistake.

Homework Statement A point charge Q resides at the origin. A particle of mass 0.005 kg carries a charge of 2 µC. The particle is released from rest at x=3 m. Its kinetic energy as it passes x=0.5 m is 0.28 J. The Coulomb constance is 8.99x10^9 N*m^2/C^2. Find the charge Q. Answer in units of...