Recent content by peterspencers

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    Torque acting on a particle in rotational motion

    Yes this gives the required result, thankyou very much for taking the time to point out my mistake. Kind regards, Peter
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    Torque acting on a particle in rotational motion

    ok, so the acceleration should just be ##-g\textit{k}##?
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    Torque acting on a particle in rotational motion

    Hi there, I have edited the initial post, apologies, I had put the unit vectors j and k in the wrong place, thankyou for correcting me. I have also included an extra line showing where the acceleration vector comes from, it is simply the second derivative of position with respect to phi + the...
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    Torque acting on a particle in rotational motion

    Homework Statement The following question involves a torque acting on a particle in rotational motion. It provides practice with the various equations for angular velocity, torque etc A particle of mass ##m## initially has position...
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    Einstein summation convention and rewriting as a matrix

    Ok, let me just get a few things cleared up in my understanding.. Firstly, the questions I am attempting to solve are on Einstein summation convention, so the question should be written.. $$\sum_{j=1}^{3} x_{j}b_{ij} = x^{j}b^{i}_{j}$$ Which means that the sum is equal to ...
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    Einstein summation convention and rewriting as a matrix

    Ok, I think I understand, many thanks for your patient help. Just to make sure I've understood correctly, if we take another example: $$\sum_{j=1}^{3} x_{j}b_{ij}$$ This would then equal.. $$x_{1}b_{i1}+x_{2}b_{i2}+x_{3}b_{i3}$$ Which is the dot product of the matrices...
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    Einstein summation convention and rewriting as a matrix

    so, just to make sure I am with you so far, the entry position of ##(A \cdot x)_{i}## $$=\sum_{j=1}^{n} a_{ij}x_{j}$$ Where ##j## represents columns in the matrix ##A## and rows in the matrix ##x## and $$(A \cdot x)=Ax$$ where A is a square matrix ...
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    Einstein summation convention and rewriting as a matrix

    $$(AB)_{ik}=\begin{pmatrix}a_{11}b_{11}+a_{12}b_{21}&a_{11}b_{12}+a_{12}b_{22}\\a_{21}b_{11}+a_{22}b_{21}&a_{21}b_{12}+a_{22}b_{22}\end{pmatrix}$$ and $$(A(\cdot)x)_{i}=a_{i1}x_{1}+a_{i2}x_{2}+... a_{in}x_{n}$$ May I ask what the correct latex code for A dot x is?
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    Einstein summation convention and rewriting as a matrix

    For the first task. $$ \begin{bmatrix}a_{ij}&a_{ij}&a_{ij}\end{bmatrix}\cdot\begin{bmatrix}b_{jk}\\b_{jk}\\b_{jk}\end{bmatrix}$$ And for the second tast...
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    Einstein summation convention and rewriting as a matrix

    To write the original question in Einstein summation, it would be.. ? $$a_{ij}b_{jk}x_{k}$$ for (i,k) = (2,3) we get.. ? $$a_{2j}b_{j3} = a_{21}b_{13}+a_{22}b_{23}+a_{23}b_{33}$$ And in the ith row and kth column we would have... ? $$a_{i1}b_{1k}+a_{i2}b_{2k}+a_{i3}b_{3k}$$
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    Einstein summation convention and rewriting as a matrix

    So, the inner sum has one repeated indicie and two free indices, so therefore has nine equations, forming a 3x3 matrix with three terms in each equation, giving us... $$...
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    Einstein summation convention and rewriting as a matrix

    Homework Statement The question asks us to write down the matrix represented by the following summation. 2. Homework Equations The question summation... $$\sum_{j,k=1}^{3} a_{ij}b_{jk}x_{k}$$ The Attempt at a Solution $$ \sum_{j,k=1}^{3} a_{ij}b_{jk}x_{k} =...
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    Proving trigonometric equations

    Homework Statement Hi there, I am attempting to prove a trigonometric equation using the half angle and double angle formulae Homework Equations See image one... The Attempt at a Solution See image two... I get stuck after the second line and can't see how to continue, please help.[/B]
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    How Does the Graph of 1/R Against E/V Relate to the Equation y = mx + c?

    I couldn't see that all you needed to do was factor out the 1/R as x
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    How Does the Graph of 1/R Against E/V Relate to the Equation y = mx + c?

    your right I am completely wrong, I took the same exam today, luckily I realized before I answered the question.
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