Recent content by pfunk22

Solution: pV / RT=n ( ((Atmospheric pressure) + (Pressure of system) ) * (volume at eq) ) / (R*T) [ (101,325 pa) + ( ((73 kg)*(9.8 m/s^2)) / (.032 m^2) ) * ( ( .032 m^2) * (.047 m) ) ] / ( (8.3 J/mol K)*(295 K) ) = .076 mols .076 mols * (6.02*10^23 mol^-1) = 4.6*10^22 molecules

i think my mistake is in the amount of pressure. i didn't take into account the whole system. how can i calculate the pressure of the entire system? specifically, the pressure of the air inside the cylinder pushing upward on the piston .Edit: ok i figured it out.

(revolutions per minute) x ( (2*pi) / (60sec) )= omega in rad/sec you want to find the change in omega over time, or alpha in rad/sec^2

I think so, i converted height to meters and temp to kelvin.

Homework Statement A smooth, well-greased insulated cylindrical container with a metal base has a light (so you can neglect its weight), airtight piston that can frictionlessly move up and down the inside of the container. A mass M = 73 kg sits on top of the piston. The piston has a circular...

Thank you so much..this was really bugging me...ended up with h= 3.02cm.

As PEi = KE(linear)f + KE(rotational)f and ended up with mgh=1/2*m*(w*r)^2 + 1/2*(2/5mr^2)*(v/r)^2

Homework Statement A solid sphere is released from rest at the top of an incline of height H and angle 30°. The sphere then rolls down the incline without slipping until it reaches the bottom of the incline, at which point the speed of the center-of-mass of the sphere is found to be 65 cm/s...