It depends what you mean by "simple and safe".
GC (or better, GC/MS) would be pretty simple and safe, it would just require equipment that most people don't have around the house.
As mentioned before, the liquid is the same in both cases, so the surface tension and viscosity of the liquid would have also been the same.
It would have been interesting to see if the same pattern formed after adding a small amount of detergent to the puddle to alter the surface tension..
Don't confuse the motions of part of a molecule with motions of an entire molecule.
In your first link, you'll notice that half of those six modes don't alter bond lengths or angles.
In the case of R=CH2, there is a double bond which can bend or twist to give the rocking, wagging, and twisting...
I have to disagree with everyone who has posted here.
It's entirely possible to have an irregular hexagon that still has 120º angles at all six corners. What ever gave you the idea that it wasn't?
Try this:
Draw an equilateral triangle, and make marks at the 1/4 and 3/4 points along each...
Since you asked:
I was just pointing out that the way you plot orbitals isn't the normal way you plot a function.
I'm not just being pedantic or trying to get the last word in...from my experience teaching, it's a non-trivial step for some people to follow.
...although it's probably better to call it the "average expected value", since it's fairly trivial to find combinations of operators and wavefunctions where the expectation value falls right where there's 0% probability density of actually getting a result.
For instance, an electron with...
Well, that's great if you can visualize four dimensions to plot it in, or visualize the probability density as the turbidity of a fog...
But the standard way to "plot" an orbital is to pick a cutoff value for the probability density such that the combined areas above the cutoff value have a...
Think of the total wavefunction as the product of an angular wavefunction and a radial wavefunction.
For s orbitals, there is no angular momentum, and therefore the orbitals will have spherical symmetry. This means at r=0 the wavefunction can (and generally will) be nonzero.
For other...
There are several problems with this.
1. You stated you were looking for oxygen atoms, not nitrogen atoms.
2. Suppose you had been given 0.30 moles of the salt instead of 0.05 moles. How would your calculations have been different?