Solved it.
I had to use e^-rt, use the initial velocity to give me a value for C, substitute that back in and then integrate with respect to t to give me height. From there you know that at t=0 and t=8.4, the height is 0. You can then calculate r and because you know the mass, k.
Use...
Homework Statement
An object of mass 10kg is projected upwards (from ground level) with initial velocity 60m/s. It hits the ground 8.4 seconds later.
Find the drag coefficient, k.
Homework Equations
dv/dt + rv = -g, where r = k/m
The Attempt at a Solution
I have used the...
Thanks!
So:
dU = T dS - PdV
As V is constant, dV = 0. Hence, - PdV = 0
dU = T dS
dU/dS = T
dH = T dS - V dP
As P is constant, dP = 0. Hence, - V dP = 0
dH = T dS
dH/dS = T
Hence
T = dU/dS @ constant V = dH/dS @ constant P
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Also, when you use "d" are you referring...
We have been asked the following: "For fixed compositions, show that T = (partial U/partial S)_V = (partial H/partial S)_P". There are 7 other equations after this one, but I think once I know how to solve the first one I will be ok with the rest.
We have not been provided with any relevant...