Recent content by phlstr

-200sin\left(30\right)+(0.15)(200)cos\left(30\right)+2T=-\frac{200}{32.2}a T-40=\frac{40}{32.2}b a=0.5b T=\frac{40}{32.2}b+40 2a=b T=\frac{40}{32.2}2a+40 -200sin\left(30\right)+(0.15)(200)cos\left(30\right)+2\left(\frac{40}{32.2}2a+40\right)=-\frac{200}{32.2}a...

I plugged the equations in wolfram alpha and got a=-0.534946 b=-1.06989, T=38.6709 I also tried using substitution and got the same for A... and it's negative??

So these are my equations: -200sin\left(30\right)+(0.15)(200)cos\left(30\right)+2T=-\frac{200}{32.2}a I use negative values for forces pointing downhill, and positive for pointing up. Since I assumed that the net force for block A is going down, I made the right side negative...

What do you mean by measuring up as positive?

If it's in equilibrium, I think you can sum up moments at O and resolve F to its x and y components and find the moment due to each component. Or you could just sum up forces along x and y to 0 (but since there's no angle I think you should use the moment method). **Just noticed you need the...

Hi :). But I already made the net mass*acceleration negative for A and the net force for B positive. I used the geometric constraint just for the magnitude.. and I think you mean a=0.5b. :shy:

Homework Statement coefficient of kinetic friction = 0.15 Find the acceleration of block a. Homework Equations see below The Attempt at a Solution http://www.wolframalpha.com/input/?i=-200sin30%2B0.15*200cos30%2B2x%3D-200%2F32.2*a%3Bx-40%3D40%2F32.2*b%3Ba%3D0.5*b I used x for...

Homework Statement Find the laplace transform of f(t)=(t-5)e^{-17(t-5)}u(t-5) The Attempt at a Solution The answer I got was \frac{e^{-5(s+17)}}{(s+17)^{2}}. I thought I finally understood the process, but when I plugged it into wolfram alpha, the answer I got was different...

Will a current through the ptype + metal material be very low because of the ptype material? Does a junction like a pn junction form between the ptype semiconductor and the metal? Thanks for your time.