I understand that the coordinates include Radial...I'm not sure what transverse acceleration is...(is it tangent acceleration?)
What I don't understand is the geometry that has to be used in with only 2 vectors.
If I had tangential acceleration, finding radial would be piece of cake...
I know...
What confuses me is the calculation of AC in the solutions...
Ac = (22.5)cos(53.1) + (20.2)cos36.9 = 29.7
It seems that (22.5)cos(53.1) implies that 22.5 is a hypotenuse in some triangle that got formed using Atot components. The same for 20.2. I don't see how ...:( Even if this gets us Ac's x...
Thank you for the reply. Unfortunately, it doesn't change anything in my progress :-(I found out that the angle between Atot and AC is 11.2 degrees and from there I don't see a solution
Hello,
This is my problem and the solution from the book. I don't understand how they came to the solution. I believe it's wrong and I offer my own solution(but incomplete). I would appreciate if you could explain how they arrived to their solution or if I'm right. Thanks:)
Please see below...
What the deuce! It's wichcraft not mathematics! I just solved it
the sides are c = 175, b = 168 and a = 49
49^2 + 168^2 = 175^2
Thank you Cristo, I think your presence in my posts make me think twice harder :)
Those minuses messed up calculations in the first place :)
okay this what I get then...
4c^2 + 1582c + 159250 = 0
or
2c^2 + 791c + 79625 = 0 if I divide everything by 2
c = -b +/- sqrt of(b^2 -4ac) and everything divided by 2a
however b^2 - 4ac is negative and I can't do a sqrt of a negative number.
What went wrong?
791^2 - 4(2)(79625) =...
Homework Statement
A city lot has the shape of a right triangle whose hypotehenuse is 7 ft longer that one of the other sides. Perimiter of the lot is 392 ft how long is each side.
Homework Equations
P = a + b +c = 392
hypothenuse is c^2 = a^2 + b^2
so if c is 7ft longer then one...
Berkeman thank you for your reply.
I believe the solution would be:
242 = K60^2
x = K 70^2
so
x/242 = (70^2/60^2)
x = (4900/3600)* 242 = 398.38m
It was very helpful :-)
Homework Statement
Hello,
I have a language problem that affects my Math problem :-) I hope you can assist me with this.
The Maximum range of a projectile is directly proportional to the square of it's velocity. A baseball pitcher can throw a ball at 60 min/h, with a maximum range of...
Whoaa you guys are the best!
First of all, I'm terribly sorry for confusing you all with
"I forgot to mention that k of line 1 isn't necessarily equals to k of line 2."
This is my mind playing games on me after 2 days of thinking about this problem. Nowhere has it said that these 2...
Cristo:
thank you for your reply.
It seems to me no matter how much I play with these 2 equations I always have either too many variables or get stuck with x and y square.
I forgot to mention that k of line 1 isn't necessarily equals to k of line 2.
So I don't see how writting them both...
Homework Statement
Find the values of k such that lines 3kx+8y = 5 and 6y -4kx = -1 are perpendicular.
I don't need the answer, but a push in a right direction. However, feel free to solve the equation :)
Homework Equations
1. Slope of a line is m = [y2-y1]/[x2-x1] where we have 2...