As I see, you didn't read all the post bro, the high=force acted *time/mass was wrong, next time read all the post...
s=ut+at^2/2, it's v_0t not ut , or vt - at^2/2
Homework Statement
I took a ball of mass= 530g and someone held it in a high for me, i wanted to find that high and what i did is :
1. act a force of 7N on it
2. the time of ball going down was 3s
i wanted to find the high and what i did is:
##high=force acted * time / mass##
when i...
Ehm, maybe that would be:
##a=F/m##
##a=5N/1kg=5m/s^2##
##a=\frac{Δ v}{Δ t}##
##5m/s^2=\frac{v_1-0}{t}##
I have no v_1(which i have to find) and I have no time..
If so, would that be
##v^2=v_0^2+2ax## which gives us
##v^2=0m^2/s^2+2(5m/s^2)(4m)##
##v^2=40m^2/s^2##...
Homework Statement
We have a body with mass=1kg and it's on rest. When a force of 5N acts on it , the body displaces 4m. Assume no friction
Find:
a)The work that force did
b)Velocity at the end of the distance(displace)
a)
##Work=Force * Displacement = 5N*4m = 20J##
##A=Fd=(5N)(4m)=20J##...
Homework Statement
What force is it needed to move a body from rest at velocity of 5m/s on distance 15m, for time of 2s. Assume no friction.Homework Equations
##F_{net}=ma##The Attempt at a Solution
Can I solve this problem without the mass of the body, if yes, what formula is needed? thanks...
If that would be mass divided by time , then we would have
##f=\frac{mv}{t}##, but that's the force formula, even friction is a kind of force, would that be friction's formula as well?
In this case
##F_N=mg## m = mass, g=gravity, gravity pulls down with 9.81m/s^2 so find normal force
##F_N=6kg*9.81\frac{m}{s^2}=58.86N##
If you're trying to move the body in constant velocity then
##F_{net}=0## because:
##F_{net}=ma##
##F-F_f=ma##
##F-F_f=m * 0##
##F-F_f=0## so friction is...
In this case that would be ##b=m/t→kg/s * v → m/s = kgm/s^2=N##, so mass times time times velocity gives us air friction but why is that b negative then?
In this formula v is not squared. but if b is coefficient, how would we win Newton for friction
coefficient =0.3 (example)
v=3m/s
##f_{air}=-bv=(-0.3)(3m/s)## gives us m/s , but not Newton?