Experiment with forces - Formula question

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Homework Help Overview

The discussion revolves around a physics experiment involving a ball of mass 530g, where a force of 7N is applied to determine the height from which the ball falls over a time period of 3 seconds. The original poster attempts to derive a formula for height based on the force, time, and mass, leading to questions about the role of gravity in their calculations.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants discuss the validity of the original poster's formula for height, questioning the absence of gravity in their calculations. There are references to established equations of motion and energy conservation as alternative approaches.

Discussion Status

The discussion is ongoing, with some participants providing insights into the relationship between the original formula and established physics principles. There is a recognition of the need for clarification regarding the application of forces and the correct equations of motion, but no consensus has been reached.

Contextual Notes

Participants are considering the implications of the force applied to the ball and how it interacts with gravitational forces during the fall. There is a suggestion that the original poster's setup may not have adequately accounted for gravity, leading to confusion in their calculations.

-Physician
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Homework Statement


I took a ball of mass= 530g and someone held it in a high for me, i wanted to find that high and what i did is :
1. act a force of 7N on it
2. the time of ball going down was 3s
i wanted to find the high and what i did is:
##high=force acted * time / mass##
when i calculated that, the units were wrong and i squared the time. What i won was this:
##h=\frac{Ft^2}{m}## and i got
##m=\frac{\frac{kgm}{s^2} * s^2}{kg}##
(kg simplified with kilogram, the s^2 with s^2 , and i won m)
I did the same thing again and the high was exactly as calculated ( 120.7547169811321m)(121m)
But I think there's still something wrong in formula because there's no gravity in formula , but then my friend said ##a=F/m## but in this case we have a high so gravity would be F/m, and we would still win ##h=gt^2## . Is all this right? thanks for reading !
 
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You mean the ball was in a free fall from this height?

The simplest equation you can get is [itex]h = \frac{gt^2}{2}[/itex]. Your equation [itex]h = \frac{Ft^2}{m}[/itex] is exactly this (after simplification), and the acceleration of gravity is hidden in the force:

[itex]h = \frac{Ft^2}{m} = \frac{mgt^2}{m} = gt^2[/itex],

though [itex]2[/itex] in the denominator is missing.

You can also try the conservation of energy: [itex]\frac{mv^2}{2} = mgh \rightarrow h = \frac{v^2}{2g}[/itex] but then you would have to know the final velocity (before hitting the ground).
 
Last edited:
So my formula is wrong?
 
-Physician said:
act a force of 7N on it
This was a vertically-directed force? What arrangement did you use to cause 7N to continuously act on the ball while it was falling? How did you neutralize gravity for your experiment?
the time of ball going down was 3s
i wanted to find the high and what i did is:
##high=force acted * time / mass##
So you invented your own equationhttps://www.physicsforums.com/images/icons/icon5.gif And you're surprised that it seems to give the right answer?
I'm surprised, too, but can't explain it. http://img140.imageshack.us/img140/7701/questionicon.gif

The equation you need is: s = ut + ½·at2
 
Last edited by a moderator:
As I see, you didn't read all the post bro, the high=force acted *time/mass was wrong, next time read all the post...
s=ut+at^2/2, it's v_0t not ut , or vt - at^2/2
 

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