Recent content by physickkksss

Not really sure what that means..."chiral isomers" For example, wouldn't the molecule in Q#20have chiral isomers, if you change one of the methyl groups to another configuration?

Homework Statement Looking at questions 18-20 on this webpage: http://www.utdallas.edu/~scortes/ochem/OChem1_Lecture/exercises/ch5_stereo1.pdf (Answers given on end of handout)Homework Equations Meso compounds have an internal plane of symmetryThe Attempt at a Solution Compounds #18 and #20...

Homework Statement Now what if the rock is suspended from a force meter, so that it is under the surface of the water but not on the bottom (and the string from the force meter goes through a small hole in the lid, so that mass is still there) Homework Equations The Attempt at a...

Homework Statement Container filled with water is placed on a scale. case #1 Lid is closed. Rock is placed on top of the lid. case #2 Rock is placed inside the water container, it sinks to bottom. Lid is closed. How does the weight (reading on the scale) compare in the two...

hmmmm...I know things get more complicated in real life, but this is a typical "homework" type of question, where E is created from either 1) point charges, or 2) flat plates. I am wondering whether: V = E*d and C=K A/d V=C/Q are two equivalent ways to do this

From what I know E must be considered as one of two cases: 1) E between point charges ==> E = K Q/r^2 2) E between large flat charged plates ==> E remains constant If two plates are moved backwards, would E change?

I noticed that there are two ways to go about it: one way: V = E*d...in which case V increases by factor of 2 second way: C = K A/d...which means C decreases by factor of 2 then V = Q/C...which means V increases by factor of 2 Both ways lead to the same answer (V increases by...

So is that the simple answer then?...V increases by a factor of 2? If the plates are very large, there are no changes in C or E?

I'm not sure... Doesn't E stay constant in a field with two flat charged plates? I know if they were point charges than it would be E = K Q/r^2 Just it does not make sense that if d is doubled, then V should go up by 2 (or else you could keep moving plates apart to create more voltage)...

Homework Statement Two flat charged plates create a uniform electric field (E). What happens to voltage (V) when the distance (d) is doubled? Homework Equations Voltage in uniform electric field: V = E*d Capacitance equations: V = Q/C C = K * A/d The Attempt at a Solution...

Ok so F(mag) pulls each wire together...I got that much But if the magetic fields between the wires repel each other, won't that oppose the F(mag) force? Then maybe the wires come to some kind of equilibrium, where the pull force equals the opposing force? I keep thinking of bringing two...

Well, when I draw it out: The F(mag) on the current in each wire, from the magnetic field of the othe wire, point towards each other. That is why I'd say the wires are attracting each other. But, in between the wires, the magnetic fields actually go in opposite directions (one out...

Homework Statement Two parallel wires carry current in same direction. Do they attract or repel each other? Homework Equations Magetic field (B) created around wire. Direction using Right Hand Rule. F(mag) = I(L x B) The Attempt at a Solution When I work out the...

Yeah so I guess that must be it... The soundboard, like any other object, does have its own natural frequency that it is prone to vibrate at. However, it must have the quality of not quickly dampening out other frequences, as would most other objects. That would make it good at transferring...

How does that fit with the statement: all objects have a natural frequency or set of frequencies at which they vibrate when struck, plucked, strummed or somehow disturbed Maybe its because normally objects quickly damp out frequencies other than its natural frequency, so the soundbox just...