Weight of system: water container and rock

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Homework Help Overview

The discussion revolves around the weight readings of a water container with a rock in two different scenarios: one with the rock placed on the lid and another with the rock submerged in the water. Participants explore how buoyancy and the setup affect the scale readings.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Some participants assert that the weight remains the same in both cases, while others express uncertainty based on previous experiences with buoyancy. A new scenario is introduced where the rock is suspended under the water, prompting questions about how this affects the weight reading on the scale.

Discussion Status

There is a mix of agreement and exploration of different scenarios. Some participants provide guidance on the implications of buoyancy forces, while others seek to clarify their understanding of the system's weight in varying setups.

Contextual Notes

Participants are considering the effects of buoyancy and the configuration of the rock within the container, which may lead to different interpretations of the weight readings. The discussion is framed within the context of homework constraints and the need for conceptual clarity.

physickkksss
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Homework Statement



Container filled with water is placed on a scale.

case #1 Lid is closed. Rock is placed on top of the lid.

case #2 Rock is placed inside the water container, it sinks to bottom. Lid is closed.

How does the weight (reading on the scale) compare in the two cases?

Homework Equations



The Attempt at a Solution



I think the weight is the same in the two cases.

But I have done some tricky questions involving buoyancy/weight.water level, and sometimes the answer is not so simple. Once I can confirm this answer, I will post some variants of this situation and try to see where my confusion is.
 
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physickkksss said:
I think the weight is the same in the two cases.
You are correct. Any buoyant forces acting on the rock when submerged are internal to the system and will not affect its scale weight.
 

Homework Statement



Now what if the rock is suspended from a force meter, so that it is under the surface of the water but not on the bottom

(and the string from the force meter goes through a small hole in the lid, so that mass is still there)

Homework Equations



The Attempt at a Solution



I think here the weight of the system becomes

W = (Weight of water & container) + Buoyancy force on rock

So the weight on the scale should be less than the two cases before
 
physickkksss said:
I think here the weight of the system becomes

W = (Weight of water & container) + Buoyancy force on rock

So the weight on the scale should be less than the two cases before
You are correct.
 
You are correct and this is easy to demonstrate using kitchen scales ( electronic is best)
And a force meter. If you lower the stone into the water you will see the force meter reading decrease and the scales reading increase as you described
 

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