I understand what you are saying but I am not quite sure what to do still...
i am confused why they told us why the cannon is at y=0... unless that is just to tell us to add two positives
also, i am not sure how to find mech energy... we went over it in class for just a couple minutes and...
I used the vertical velocity
in a part 1, i did 1100sin37.3 for v, and in part 2, it was a 90 degree angle
i got this formula because that's what we've been using in class... although i just posted the simplified version of it... the part where we started plugging in numbers
ok,
heres the prob:
A 21.0 kg cannon ball is fired from a cannon with a muzzle speed of 1100 m/s at an angle of 37.3° with the horizontal. A second ball is fired at an angle of 90.0°. Use the law of conservation of mechanical energy to find
(b) the total mechanical energy at the maximum...