So that means
Since my ## \Delta \mathbf{r} ## = (0.065 i + 0.06 j -0.055 k)
Therefore W = | (0.065 i + 0.06 j -0.055 k) ## \cdot ## 0.475 (143.08 i + 0 j + 228.97 k)|
= |4.4176 - 5.9818|
= 1.56 J
Am I correct here? (btw Thanks for your quick responses)
Could you tell me if this is right?
E = 270 Cos 58oi + 270 Cos 32ok
= 143.08 i + 0 j + 228.97 k
If that's my electric field I basically subtract the distance points to get (d) and put it in W = qE.d to get W. Then I can square the values, add them and square root it to get the magnitude of W?
Homework Statement
There is a uniform electric field, E = 270 N/C, parallel to the xz plane, making an angle of 32o with the positive z axis and an angle of 58o with the positive x axis. A particle with charge q= 0.475 C is moved from the point (xi = 2.0 cm, yi = 0, zi = 0) to the point (xf =...